Dear what-ever-your-name-is,

Using four 0.8 Ohm secondaries, you can acheive the following:

All 4 in parallel = 0.8 Ohms
2 in series paralled with two more in series = 3.2 Ohms
3 in series = 7.2 Ohms.
All four in series = 12.8 Ohms.

Good luck,
Randy Ott

"·à¤l¤f" wrote in message
...
How to get 0.8 Ohm 3.2 Ohm 7.4 Ohm and 12.5 Ohm using four 0.8 Ohm
secondaries in:
http://stiftsbogtrykkeriet.dk/~mcs/Transformer.html






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