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#1
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Hiyee,
I know I know...this is a tube amp group...but since you all are so good at it...I might as well just post here...I need a little low-pass filter that will work for a Solid-State amp that I plan to convert to a Subwoofer amp...say a few parts hooked together...like a 1st order thingy...I'm not really familiar with this...I guess my cut-off point will be like 87Hz or something?? can you guys recommend a schematic and some component values?? Thanks in advance. Regards, li_gangyi |
#2
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If you got to www.partsexpress.com they sell a little low pass (and
high pass) plug in modules that may be what your looking for. Don't know how good they are but they are cheap. On Sun, 13 Jul 2003 23:48:53 +0800, "li_gangyi" wrote: Hiyee, I know I know...this is a tube amp group...but since you all are so good at it...I might as well just post here...I need a little low-pass filter that will work for a Solid-State amp that I plan to convert to a Subwoofer amp...say a few parts hooked together...like a 1st order thingy...I'm not really familiar with this...I guess my cut-off point will be like 87Hz or something?? can you guys recommend a schematic and some component values?? Thanks in advance. Regards, li_gangyi Dan Santoni DTS Audio Hamilton, ON Canada |
#3
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Maybe you are lokking for this ......
http://www.ultranalog.com/jennifer_lowpass/ It uses pencil tubes , but if you take a look at that data it might be not that hard to convert it to "normal" tubes . Ronald . "li_gangyi" schreef in bericht ... Hmm...has anyone tried building one...coz I dun really think shipping stuff from the US is such a good idea...although we now have the free trade agreement with the US... "DTS Audio" wrote in message ... If you got to www.partsexpress.com they sell a little low pass (and high pass) plug in modules that may be what your looking for. Don't know how good they are but they are cheap. On Sun, 13 Jul 2003 23:48:53 +0800, "li_gangyi" wrote: Hiyee, I know I know...this is a tube amp group...but since you all are so good at it...I might as well just post here...I need a little low-pass filter that will work for a Solid-State amp that I plan to convert to a Subwoofer amp...say a few parts hooked together...like a 1st order thingy...I'm not really familiar with this...I guess my cut-off point will be like 87Hz or something?? can you guys recommend a schematic and some component values?? Thanks in advance. Regards, li_gangyi Dan Santoni DTS Audio Hamilton, ON Canada |
#4
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![]() li_gangyi wrote: Hiyee, I know I know...this is a tube amp group...but since you all are so good at it...I might as well just post here...I need a little low-pass filter that will work for a Solid-State amp that I plan to convert to a Subwoofer amp...say a few parts hooked together...like a 1st order thingy...I'm not really familiar with this...I guess my cut-off point will be like 87Hz or something?? can you guys recommend a schematic and some component values?? Thanks in advance. Regards, li_gangyi I have built a couple of subwoofer projects which included a 12" speaker in a large ported box driven by an SS amp to augment a small pair of floor standing speakers. The L and R signal from the line stage part of the integrated tube power amp, ( used for most of the signal ) was taken out with two cables to two 22 k resistors, and at the join of these two R is a mono signal, and this is then fed to a high input impedance emitter follower transistor stage, with a cap from base to ground of 0.15 uF, giving a first order pole at 96 Hz, The emitter output from the transistor give a low impedance drive ( just like a cathode follower ) to another RC low pass filter, LPF, 4.7k and 0.33 uF, which gives a pole of 100 Hz. Then another LPF with 22k and 0.082 uF, then another single transistor, with its emitter output cap coupled to a 10k gain pot. So all up, a 3rd order filter. The power amp has an RC input filter with a pole at 150 Hz. So ultimately, there is a 4th order filter above 150 Hz, which is 24 dB/octave, and you NEED this level of filtering so that all you get from the sub is a deep rumble, and its very hard to tell if there is someone singing, or playing a saxaphone. The above filter, and 25v power supply is very cheap, and the cost to DIY should be no more than USD $15.00 The filter I built is powered from the SS amp power supply. It draws only 10 mA. In my client's case, I had 4 sets of 3 different caps, to give cut off points at 27, 54 and 68 Hz, to suit the speakers the guy already has, and allow him to experiment for the best sound. A 3 position x 4 pole switch allows this. His speakers, Vienna Acoustics, with two small 5" woofer-mids, have a cut off at 55 Hz, and guess what, he prefers the setting I made for 54 Hz, although his son prefers 68 Hz, and greater volume on rappy music. With a bit of a learn, and a bit of a do, you can afford 10 bucks, eh? Patrick Turner. |
#5
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Hiyee,
Perhaps you can gimmi a quickly drawn out schematic...thanks in advance. Regards, li_gangyi "Patrick Turner" wrote in message ... li_gangyi wrote: Hiyee, I know I know...this is a tube amp group...but since you all are so good at it...I might as well just post here...I need a little low-pass filter that will work for a Solid-State amp that I plan to convert to a Subwoofer amp...say a few parts hooked together...like a 1st order thingy...I'm not really familiar with this...I guess my cut-off point will be like 87Hz or something?? can you guys recommend a schematic and some component values?? Thanks in advance. Regards, li_gangyi I have built a couple of subwoofer projects which included a 12" speaker in a large ported box driven by an SS amp to augment a small pair of floor standing speakers. The L and R signal from the line stage part of the integrated tube power amp, ( used for most of the signal ) was taken out with two cables to two 22 k resistors, and at the join of these two R is a mono signal, and this is then fed to a high input impedance emitter follower transistor stage, with a cap from base to ground of 0.15 uF, giving a first order pole at 96 Hz, The emitter output from the transistor give a low impedance drive ( just like a cathode follower ) to another RC low pass filter, LPF, 4.7k and 0.33 uF, which gives a pole of 100 Hz. Then another LPF with 22k and 0.082 uF, then another single transistor, with its emitter output cap coupled to a 10k gain pot. So all up, a 3rd order filter. The power amp has an RC input filter with a pole at 150 Hz. So ultimately, there is a 4th order filter above 150 Hz, which is 24 dB/octave, and you NEED this level of filtering so that all you get from the sub is a deep rumble, and its very hard to tell if there is someone singing, or playing a saxaphone. The above filter, and 25v power supply is very cheap, and the cost to DIY should be no more than USD $15.00 The filter I built is powered from the SS amp power supply. It draws only 10 mA. In my client's case, I had 4 sets of 3 different caps, to give cut off points at 27, 54 and 68 Hz, to suit the speakers the guy already has, and allow him to experiment for the best sound. A 3 position x 4 pole switch allows this. His speakers, Vienna Acoustics, with two small 5" woofer-mids, have a cut off at 55 Hz, and guess what, he prefers the setting I made for 54 Hz, although his son prefers 68 Hz, and greater volume on rappy music. With a bit of a learn, and a bit of a do, you can afford 10 bucks, eh? Patrick Turner. |
#6
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In article , Patrick Turner
wrote: I have built a couple of subwoofer projects which included a 12" speaker in a large ported box driven by an SS amp to augment a small pair of floor standing speakers. The L and R signal from the line stage part of the integrated tube power amp, ( used for most of the signal ) was taken out with two cables to two 22 k resistors, and at the join of these two R is a mono signal, and this is then fed to a high input impedance emitter follower transistor stage, Don't these 22k resistors create a noticeable amount of cross talk, given the relatively high impedances involved in tube amps? Why not include a couple of high input impedance emitter follower transistor stages in front of the resistors? Regards, John Byrns Surf my web pages at, http://users.rcn.com/jbyrns/ |
#7
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![]() John Byrns wrote: In article , Patrick Turner wrote: I have built a couple of subwoofer projects which included a 12" speaker in a large ported box driven by an SS amp to augment a small pair of floor standing speakers. The L and R signal from the line stage part of the integrated tube power amp, ( used for most of the signal ) was taken out with two cables to two 22 k resistors, and at the join of these two R is a mono signal, and this is then fed to a high input impedance emitter follower transistor stage, Don't these 22k resistors create a noticeable amount of cross talk, given the relatively high impedances involved in tube amps? Not much cross talk because the junction of the R is shunted with a cap to ground, and the bass signals are usually the same for both channels. The take off point from the line stage is from a relatively low impedance point, being the wiper of the 100k log volume controls and in normal use, its at a low impedance setting; at 12 oclock, at -20dB, the output impedance of the pot is 9k. The stereo info is contained in F above 250 Hz, and the cap shunting the 22k x 2 prevents much cross talk above this F. By 5 kHz, where you sure don't want any cross talk, my method is quite OK. Why not include a couple of high input impedance emitter follower transistor stages in front of the resistors? This is the more purist way of doing it, but then its an extra stage. Mr Gangyi has to learn about transistors and filters. Before I ferret through a mountain of paper circuits I've used, and scan them in and transmit them, I think he ought to just try fooling around with a few 10c small signal transistors, and a few R and C elements. It will be a revelation. He should find out that in common emmitter mode, with a bypassed emitter, the transistors producing 3 vrms are hopelessly distorted, over several %, but at 4 mA, the gain will be huge. Then when the emitter R isn't bypassed, the gain will plummet, and the thd will then seem similar to a tube, but still not as low. Then in emitter follower, the transistor is at its best, ie, has the lowest thd, and competes well with a cathode follower. The way I did it means there is very low thd, and very little circuit complexity. This sort of project is just perfect to train the mind to basic analog electronics, some understanding of filters, and cascading them, settinjg bias currents, choosing load values, understanding load lines, and it'll put a rumble in a lounge. There would be many readers wondering where to start; I suggest they buy a few small NPN signal transistors, and some pre drilled board for experimental circuits, some 0.6 mm dia solid hook up wire, and first build a little +/- 12 volt supply, and a volt meter, and a book about basic transistor circuits. Opamps could easily be used instead, but in this case, there is no need. Since my idea needs emitter followers, cathode followers made from 12AU7, 12AT7 would be quite excellent. But there is a lot more trouble to be gone to for just a bit of low bass. There is no need for any gain in the active devices. The following SS power amp input sensitivity can be adjusted for say 0.5 v for full power by adjusting the FB network if need be. Some presettable gain pot for the sub amp is usually necessary. Patrick Turner. Regards, John Byrns Surf my web pages at, http://users.rcn.com/jbyrns/ |
#8
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Hey hey~! I'm not a Mr. yet~! at least in a "lawful" manner coz I'm 14...and
yeah...I have messed with some filters...but I guess it's my component values that need changing...coz they dun cut at the frequency that I need...and I dun use transistors...only passive...meaning I've got no boost...right?? Can you point me in the right direction to build a simple...filter... "Patrick Turner" wrote in message ... John Byrns wrote: In article , Patrick Turner wrote: I have built a couple of subwoofer projects which included a 12" speaker in a large ported box driven by an SS amp to augment a small pair of floor standing speakers. The L and R signal from the line stage part of the integrated tube power amp, ( used for most of the signal ) was taken out with two cables to two 22 k resistors, and at the join of these two R is a mono signal, and this is then fed to a high input impedance emitter follower transistor stage, Don't these 22k resistors create a noticeable amount of cross talk, given the relatively high impedances involved in tube amps? Not much cross talk because the junction of the R is shunted with a cap to ground, and the bass signals are usually the same for both channels. The take off point from the line stage is from a relatively low impedance point, being the wiper of the 100k log volume controls and in normal use, its at a low impedance setting; at 12 oclock, at -20dB, the output impedance of the pot is 9k. The stereo info is contained in F above 250 Hz, and the cap shunting the 22k x 2 prevents much cross talk above this F. By 5 kHz, where you sure don't want any cross talk, my method is quite OK. Why not include a couple of high input impedance emitter follower transistor stages in front of the resistors? This is the more purist way of doing it, but then its an extra stage. Mr Gangyi has to learn about transistors and filters. Before I ferret through a mountain of paper circuits I've used, and scan them in and transmit them, I think he ought to just try fooling around with a few 10c small signal transistors, and a few R and C elements. It will be a revelation. He should find out that in common emmitter mode, with a bypassed emitter, the transistors producing 3 vrms are hopelessly distorted, over several %, but at 4 mA, the gain will be huge. Then when the emitter R isn't bypassed, the gain will plummet, and the thd will then seem similar to a tube, but still not as low. Then in emitter follower, the transistor is at its best, ie, has the lowest thd, and competes well with a cathode follower. The way I did it means there is very low thd, and very little circuit complexity. This sort of project is just perfect to train the mind to basic analog electronics, some understanding of filters, and cascading them, settinjg bias currents, choosing load values, understanding load lines, and it'll put a rumble in a lounge. There would be many readers wondering where to start; I suggest they buy a few small NPN signal transistors, and some pre drilled board for experimental circuits, some 0.6 mm dia solid hook up wire, and first build a little +/- 12 volt supply, and a volt meter, and a book about basic transistor circuits. Opamps could easily be used instead, but in this case, there is no need. Since my idea needs emitter followers, cathode followers made from 12AU7, 12AT7 would be quite excellent. But there is a lot more trouble to be gone to for just a bit of low bass. There is no need for any gain in the active devices. The following SS power amp input sensitivity can be adjusted for say 0.5 v for full power by adjusting the FB network if need be. Some presettable gain pot for the sub amp is usually necessary. Patrick Turner. Regards, John Byrns Surf my web pages at, http://users.rcn.com/jbyrns/ |
#9
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![]() li_gangyi wrote: Hey hey~! I'm not a Mr. yet~! at least in a "lawful" manner coz I'm 14...and yeah...I have messed with some filters...but I guess it's my component values that need changing...coz they dun cut at the frequency that I need...and I dun use transistors...only passive...meaning I've got no boost...right?? Can you point me in the right direction to build a simple...filter... Well, the simplest (first order) filter is one resistor and one capacitor. The resistor is in series, the capacitor is shunted to ground. Like this (you'll need to have a fixed-width font to see this properly): o--------/\/\/\/\-------+------o R | | input ----- output ----- C | | o-----------------------+------o The value of R should be at least an order of magnitude lower than the impedance at the output (in other words, in parallel with C). For most tube amps this will be quite high, 100k to 1M or so, usually the volume control pot. So, for example, if it's 500k, you'd want to choose R to be around 50k. Let's choose 47k. Then choose your corner frequency. Let's say you want the rolloff to start at 50 Hz. Multiply the frequency F by the resistance R, and divide that into 159,000 for the value of C in microfarads. In our example, 47,000 * 50 = 2,350,000. Divide that into 159,000 and we get about 0.068 uF. The formula is derived from the formula for capacitive reactance. The 3 dB corner will be that frequency at which the reactance equals the resistance R. It's given by the equation: F=1/(2*Pi*R*C) with R in ohms, C in farads, F in Hertz, Pi ~ 3.1416. Cheers, Fred -- +--------------------------------------------+ | Music: http://www3.telus.net/dogstarmusic/ | | Projects, Vacuum Tubes & other stuff: | | http://www.dogstar.dantimax.dk | +--------------------------------------------+ |
#10
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![]() Fred Nachbaur wrote: li_gangyi wrote: Hey hey~! I'm not a Mr. yet~! at least in a "lawful" manner coz I'm 14...and yeah...I have messed with some filters...but I guess it's my component values that need changing...coz they dun cut at the frequency that I need...and I dun use transistors...only passive...meaning I've got no boost...right?? Can you point me in the right direction to build a simple...filter... Well, the simplest (first order) filter is one resistor and one capacitor. The resistor is in series, the capacitor is shunted to ground. Like this (you'll need to have a fixed-width font to see this properly): o--------/\/\/\/\-------+------o R | | input ----- output ----- C | | o-----------------------+------o The value of R should be at least an order of magnitude lower than the impedance at the output (in other words, in parallel with C). For most tube amps this will be quite high, 100k to 1M or so, usually the volume control pot. So, for example, if it's 500k, you'd want to choose R to be around 50k. Let's choose 47k. Then choose your corner frequency. Let's say you want the rolloff to start at 50 Hz. Multiply the frequency F by the resistance R, and divide that into 159,000 for the value of C in microfarads. In our example, 47,000 * 50 = 2,350,000. Divide that into 159,000 and we get about 0.068 uF. The formula is derived from the formula for capacitive reactance. The 3 dB corner will be that frequency at which the reactance equals the resistance R. It's given by the equation: F=1/(2*Pi*R*C) with R in ohms, C in farads, F in Hertz, Pi ~ 3.1416. Cheers, Fred Thanks Fred, you have laid out a splendid path for our lad to tread, I hope he steps carefully, and asks many questions on the way; if not, he isn't learning much. A few old electronics text books might help him along some more, and the answers to his questions are in them, which might make our lives easier. Patrick Turner. -- +--------------------------------------------+ | Music: http://www3.telus.net/dogstarmusic/ | | Projects, Vacuum Tubes & other stuff: | | http://www.dogstar.dantimax.dk | +--------------------------------------------+ |
#11
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![]() Patrick Turner wrote: Fred Nachbaur wrote: li_gangyi wrote: Hey hey~! I'm not a Mr. yet~! at least in a "lawful" manner coz I'm 14...and yeah...I have messed with some filters...but I guess it's my component values that need changing...coz they dun cut at the frequency that I need...and I dun use transistors...only passive...meaning I've got no boost...right?? Can you point me in the right direction to build a simple...filter... Well, the simplest (first order) filter is one resistor and one capacitor. The resistor is in series, the capacitor is shunted to ground. Like this (you'll need to have a fixed-width font to see this properly): o--------/\/\/\/\-------+------o R | | input ----- output ----- C | | o-----------------------+------o The value of R should be at least an order of magnitude lower than the impedance at the output (in other words, in parallel with C). For most tube amps this will be quite high, 100k to 1M or so, usually the volume control pot. So, for example, if it's 500k, you'd want to choose R to be around 50k. Let's choose 47k. Then choose your corner frequency. Let's say you want the rolloff to start at 50 Hz. Multiply the frequency F by the resistance R, and divide that into 159,000 for the value of C in microfarads. In our example, 47,000 * 50 = 2,350,000. Divide that into 159,000 and we get about 0.068 uF. The formula is derived from the formula for capacitive reactance. The 3 dB corner will be that frequency at which the reactance equals the resistance R. It's given by the equation: F=1/(2*Pi*R*C) with R in ohms, C in farads, F in Hertz, Pi ~ 3.1416. Cheers, Fred Thanks Fred, you have laid out a splendid path for our lad to tread, I hope he steps carefully, and asks many questions on the way; if not, he isn't learning much. A few old electronics text books might help him along some more, and the answers to his questions are in them, which might make our lives easier. Patrick Turner. Thanks, Patrick. Yes, there's nothing better than learning the basics well, and thinking things out oneself. It's nice to have a starting point though. You gave some good tips in your reply also, and in reading it I realized that I should have mentioned the point about having to have a low input impedance into the filter. Furthermore, the input impedance may have to be accounted for in choosing the value for "R". For example, if the input to the filter is the output of a typical CD player, the impedance is usually on the order of a thousand ohms or so, and therefore can be safely ignored. However, if it's the output of a tube preamp, it might be considerably higher; say, on the order of 10,000 ohms or maybe even more. In this case, this value has to be subtracted from the calculated value of "R" in order for the filter to work as expected. Cheers to all RATs, young, old, and inbetween, Fred -- +--------------------------------------------+ | Music: http://www3.telus.net/dogstarmusic/ | | Projects, Vacuum Tubes & other stuff: | | http://www.dogstar.dantimax.dk | +--------------------------------------------+ |
#12
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![]() Fred Nachbaur wrote: Patrick Turner wrote: Fred Nachbaur wrote: li_gangyi wrote: Hey hey~! I'm not a Mr. yet~! at least in a "lawful" manner coz I'm 14...and yeah...I have messed with some filters...but I guess it's my component values that need changing...coz they dun cut at the frequency that I need...and I dun use transistors...only passive...meaning I've got no boost...right?? Can you point me in the right direction to build a simple...filter... Well, the simplest (first order) filter is one resistor and one capacitor. The resistor is in series, the capacitor is shunted to ground. Like this (you'll need to have a fixed-width font to see this properly): o--------/\/\/\/\-------+------o R | | input ----- output ----- C | | o-----------------------+------o The value of R should be at least an order of magnitude lower than the impedance at the output (in other words, in parallel with C). For most tube amps this will be quite high, 100k to 1M or so, usually the volume control pot. So, for example, if it's 500k, you'd want to choose R to be around 50k. Let's choose 47k. Then choose your corner frequency. Let's say you want the rolloff to start at 50 Hz. Multiply the frequency F by the resistance R, and divide that into 159,000 for the value of C in microfarads. In our example, 47,000 * 50 = 2,350,000. Divide that into 159,000 and we get about 0.068 uF. The formula is derived from the formula for capacitive reactance. The 3 dB corner will be that frequency at which the reactance equals the resistance R. It's given by the equation: F=1/(2*Pi*R*C) with R in ohms, C in farads, F in Hertz, Pi ~ 3.1416. Cheers, Fred Thanks Fred, you have laid out a splendid path for our lad to tread, I hope he steps carefully, and asks many questions on the way; if not, he isn't learning much. A few old electronics text books might help him along some more, and the answers to his questions are in them, which might make our lives easier. Patrick Turner. Thanks, Patrick. Yes, there's nothing better than learning the basics well, and thinking things out oneself. It's nice to have a starting point though. You gave some good tips in your reply also, and in reading it I realized that I should have mentioned the point about having to have a low input impedance into the filter. Furthermore, the input impedance may have to be accounted for in choosing the value for "R". Indeed, but when he starts using equations, and working out what a filter response should be, and he doesn't mesure that, then he should ask, why is this not working out? where is the extra resistance? I asked questions like this, and went looking, and then more questions, and eventually, I got to bed at 5 in the morning. For example, if the input to the filter is the output of a typical CD player, the impedance is usually on the order of a thousand ohms or so, and therefore can be safely ignored. Indeed. Usually if a signal source impedance is 1/10 of the minimum filter input impedance, then the results measured about tally with results calculated. However, if it's the output of a tube preamp, it might be considerably higher; say, on the order of 10,000 ohms or maybe even more. In this case, this value has to be subtracted from the calculated value of "R" in order for the filter to work as expected. Indeed. You can't tell the youngans everything, you gotta let them find some things out, their empty minds are easily filled, but not so common is a burning passion to learn. Cheers to all RATs, young, old, and inbetween, Fred Indeed, Patrick Turner. -- +--------------------------------------------+ | Music: http://www3.telus.net/dogstarmusic/ | | Projects, Vacuum Tubes & other stuff: | | http://www.dogstar.dantimax.dk | +--------------------------------------------+ |
#13
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Hiyee,
WOW~! Thanks for the nice replies...and yeah...I did try the first order filter...last time...I parelled a 50k pot with a 10K resistor to adjust the cut-off...and a 68nF capacitor...sound wasn't that bad...but I DO need to improve on it...any ideas?? I got the calculations and stuff from this site... http://www.t-linespeakers.org/tech/f...ssiveHLxo.html the 10K value was what I have...should I use another value?? Regards, li_gangyi P.S this was/is the kinda discussion that I was hoping for in the first place... "Patrick Turner" wrote in message ... li_gangyi wrote: Hey hey~! I'm not a Mr. yet~! at least in a "lawful" manner coz I'm 14...and yeah...I have messed with some filters...but I guess it's my component values that need changing...coz they dun cut at the frequency that I need...and I dun use transistors...only passive...meaning I've got no boost...right?? Can you point me in the right direction to build a simple...filter... "Patrick Turner" wrote in message Master Gangyi, I was only suggesting you TRY to work a bit more on your own on this one, because you might teach yourself about the fundementals. The first thing to remember about RC filters is that a low drive impedance works best. So, build one. It can be emitter follower, or a cathode follower, such as at the last stage of the preamp at http://www.turneraudio.com.au/htmlwe...tubepreamp.htm The input impedance is high, output impedance is low, and to REALLY understand this, try connecting different value loads to the output and measuring the voltage drop and change to output current. Then from ohm's law, the value of output resistance can be calculated. A cathode follower can have an LPF with R, then a C to ground, as the input circuit, and then a two stage RC LPF at the output, and this will give a sharp cut off characteristic, rather than have 3 cascaded RC section with no tube. The cut off is too gradual at first, and to get a high slope of attenuation by the time we get to 150 Hz, and above, the initial -3dB pole would have to be at 30 Hz. The only way you are going to know what you got is to measure the response accurately. This means you need a sig gene, with a flat response output down to 2 Hz, and preferably a CRO, but at least signal voltmeter, most digital types will do, a pencil, and exercise book, where you can get into the habit of drawing vertical lines across the page to indicate where 10Hz,100Hz,1kHz,10kHz,100kHz are, so that intermediate frequencies can be located. Try to get some logarithmic graph paper for this, but its a lazy lads way of approach. I just draw up a page with a ruler with approximate positions of the main F, at 10, 20, 32, 50, and 100 for each decade, and its easy to guess where 15, 25, 40, 60, 70 will appear, once you see how a log scale appears. Then I use each line down the page in the exercise book to represent a -3dB drop in signal level, so two lines means -6dB which is signal /2, and 4 lines means -12dB, and 6 lines means -18dB, and so on. Try plotting the response of an LPF with your sig gene as the low impedance signal source. This is really basic, but in my school science studies after age 14, this sort of approach in the science lab was taught to me all those years ago. It occurred to me as a teenager, that it seemed perfectly sensible to try to describe accurately what I was doing in neat notes in a book. Once you actually do this sort of thing, you get a clear mental picture about filters. Transistors frequency capability are entirely adequate for all audio frequencies. Once understood, without fear, its easy to use them. Same goes for tubes, but its more work to set one up. Transistors are boring little black things, but nevertheless, they do a lot, so no need to ignore them. One can dislike them easily, and prefer something larger sized, which glows in the dark, but still we should understand both forms of technology, to understand strength and weakness. Opamps are also conglomerations of many transistors within, about which it sometimes is extremely difficult to comprehend in one single simple thought. But the overall fundemental purpose of a chip can be understood, and its all we need to know for its use. Same could be said about an old radio, or TV, which uses tubes, and after time and study, each part becomes understandable. But not without learning the basics. OK, so try to think of little things seperately at first, and then later you will have no trouble joining them together. Your brain won't fall out of your head trying, I assure you. Knowledge can only be learned by you, it isn't something given to you, although the path is laid out for you to learn, if you want to. Patrick Turner. |
#14
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![]() li_gangyi wrote: Hiyee, WOW~! Thanks for the nice replies...and yeah...I did try the first order filter...last time...I parelled a 50k pot with a 10K resistor to adjust the cut-off...and a 68nF capacitor...sound wasn't that bad...but I DO need to improve on it...any ideas?? I got the calculations and stuff from this site... http://www.t-linespeakers.org/tech/f...ssiveHLxo.html the 10K value was what I have...should I use another value?? Regards, li_gangyi P.S this was/is the kinda discussion that I was hoping for in the first place... That site above seems to be OK, so keep going, and carefully measure everything as you go. It should then sound OK. Patrick Turner. "Patrick Turner" wrote in message ... li_gangyi wrote: Hey hey~! I'm not a Mr. yet~! at least in a "lawful" manner coz I'm 14...and yeah...I have messed with some filters...but I guess it's my component values that need changing...coz they dun cut at the frequency that I need...and I dun use transistors...only passive...meaning I've got no boost...right?? Can you point me in the right direction to build a simple...filter... "Patrick Turner" wrote in message Master Gangyi, I was only suggesting you TRY to work a bit more on your own on this one, because you might teach yourself about the fundementals. The first thing to remember about RC filters is that a low drive impedance works best. So, build one. It can be emitter follower, or a cathode follower, such as at the last stage of the preamp at http://www.turneraudio.com.au/htmlwe...tubepreamp.htm The input impedance is high, output impedance is low, and to REALLY understand this, try connecting different value loads to the output and measuring the voltage drop and change to output current. Then from ohm's law, the value of output resistance can be calculated. A cathode follower can have an LPF with R, then a C to ground, as the input circuit, and then a two stage RC LPF at the output, and this will give a sharp cut off characteristic, rather than have 3 cascaded RC section with no tube. The cut off is too gradual at first, and to get a high slope of attenuation by the time we get to 150 Hz, and above, the initial -3dB pole would have to be at 30 Hz. The only way you are going to know what you got is to measure the response accurately. This means you need a sig gene, with a flat response output down to 2 Hz, and preferably a CRO, but at least signal voltmeter, most digital types will do, a pencil, and exercise book, where you can get into the habit of drawing vertical lines across the page to indicate where 10Hz,100Hz,1kHz,10kHz,100kHz are, so that intermediate frequencies can be located. Try to get some logarithmic graph paper for this, but its a lazy lads way of approach. I just draw up a page with a ruler with approximate positions of the main F, at 10, 20, 32, 50, and 100 for each decade, and its easy to guess where 15, 25, 40, 60, 70 will appear, once you see how a log scale appears. Then I use each line down the page in the exercise book to represent a -3dB drop in signal level, so two lines means -6dB which is signal /2, and 4 lines means -12dB, and 6 lines means -18dB, and so on. Try plotting the response of an LPF with your sig gene as the low impedance signal source. This is really basic, but in my school science studies after age 14, this sort of approach in the science lab was taught to me all those years ago. It occurred to me as a teenager, that it seemed perfectly sensible to try to describe accurately what I was doing in neat notes in a book. Once you actually do this sort of thing, you get a clear mental picture about filters. Transistors frequency capability are entirely adequate for all audio frequencies. Once understood, without fear, its easy to use them. Same goes for tubes, but its more work to set one up. Transistors are boring little black things, but nevertheless, they do a lot, so no need to ignore them. One can dislike them easily, and prefer something larger sized, which glows in the dark, but still we should understand both forms of technology, to understand strength and weakness. Opamps are also conglomerations of many transistors within, about which it sometimes is extremely difficult to comprehend in one single simple thought. But the overall fundemental purpose of a chip can be understood, and its all we need to know for its use. Same could be said about an old radio, or TV, which uses tubes, and after time and study, each part becomes understandable. But not without learning the basics. OK, so try to think of little things seperately at first, and then later you will have no trouble joining them together. Your brain won't fall out of your head trying, I assure you. Knowledge can only be learned by you, it isn't something given to you, although the path is laid out for you to learn, if you want to. Patrick Turner. |
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