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Patrick
 
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Default cable length needed to create phase shift?

how much of a difference in cable length would it take to create a
noticeable phase difference between two signals coming from the same
source simultaneously? i.e., wouldn't a 1000' xlr cable arrive at the
pre, recorder, etc. much later than the signal that only had to travel
through a 25' xlr cable?
thanks,
patrick
  #2   Report Post  
ScotFraser
 
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Default cable length needed to create phase shift?

i.e., wouldn't a 1000' xlr cable arrive at the
pre, recorder, etc. much later than the signal that only had to travel
through a 25' xlr cable?

The signal travels at the speed of light. Yes, theoretically it will arrive
later through the longer cable. No human will ever detect the arrival
difference, though.


Scott Fraser
  #3   Report Post  
Scott Dorsey
 
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Default cable length needed to create phase shift?

Patrick wrote:
how much of a difference in cable length would it take to create a
noticeable phase difference between two signals coming from the same
source simultaneously? i.e., wouldn't a 1000' xlr cable arrive at the
pre, recorder, etc. much later than the signal that only had to travel
through a 25' xlr cable?



Okay, let's pick worst case. You have a 20 KHz signal, and you want to
delay it a quarter wave. One cycle is 0.05 milliseconds, so a quarter
wave is 0.0125 milliseconds.

This really isn't much of a difference, but it's enough to be noticeable
if you're picky and sum it with the original signal and have really good
ears and monitors.

Now, C is 186 miles per millisecond. Going through Belden cat-5 cable
gives you a speed of .68C, which is 126.48 miles per millisecond.

So, at that rate, how much cable do you need to go 0.0125 milliseconds?
About a mile and a half. Not a huge amount, but more than you'll encounter
in the studio. A thousand feet is nothing.
--scott
--
"C'est un Nagra. C'est suisse, et tres, tres precis."
  #5   Report Post  
S O'Neill
 
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Default cable length needed to create phase shift?

Light travels almost a billion feet per second in a vacuum. The signal in a
cable moves about 3/4 of that. It takes a little over 1.35 microsecond to
travel that 1000'. If a latency of 1 millisecond is acceptable (in MIDI circles
it seems to be), a cable run of up to about 740,000 feet (140 miles) should be ok.

But you'd have to coil that cable up to sit next to the 25' cable if you wanted
to find out if you could hear the delay.

Your first question, about a noticeable phase difference, varies with frequency
and your definition of "noticeable".


Patrick wrote:

how much of a difference in cable length would it take to create a
noticeable phase difference between two signals coming from the same
source simultaneously? i.e., wouldn't a 1000' xlr cable arrive at the
pre, recorder, etc. much later than the signal that only had to travel
through a 25' xlr cable?
thanks,
patrick




  #8   Report Post  
Ben Bradley
 
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Default cable length needed to create phase shift?

In rec.audio.pro, Chris Hornbeck
wrote:

On Thu, 30 Oct 2003 22:09:17 +0000 (UTC), (Jay
Kadis) wrote:

At the velocity electrons travel in metal (nearly 186,000 miles/sec or almost a
trillion (10^9) feet/sec), that length difference wouldn't matter.


This looks to be the first error in the thread so far... the power
of 10 is correct, but it's called (at least in the USA) a billion - a
trillion would be 10^12. Or is a trillion actually 10^9 "over there?"
I know many of these words change meaning by three orders of magnitude
when they cross The Pond. I recall a "billiard" but I forget where it
goes in the sequence.

Strangely enough, electrons themselves only travel about as fast
as a person can walk.


Does anyone know how this was determined? I've always been
fascinated at how these things are discovered, like how the electron
(or 'quantum of') charge was determined with tiny charged oil drops
under a microscope.

A signal / impulse travels essentially in the
insulators of a cable, typically at about .7C.
At least, this is the number that several knowledgable folk on
this board accept for typical cables. In a recent thread, I
dredged a number of .1C out of ancient memory, and was soon
disabused of the idea.
There's also something called drift velocity, but I've not
seen it translated down to my level of understanding.


In this case the 'water pipe' analogy of electricity flow works
well. When you turn the valve to make water flow (into, let's say, a
hose already full of water but at low pressure), the pressure increase
travels at the speed of sound through water (which is I forget, but a
few times faster than it is in air), but the actual water only travels
a few feet per second.

Curiouser and curiouser...


Chris Hornbeck
new email address


  #10   Report Post  
Michael R. Kesti
 
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Default cable length needed to create phase shift?

Ben Bradley wrote:

snip

What could be a real problem with 1000 feet of cable is high
frequency rolloff due to the capacitance of the cable.


Hmmm... Everybody's been discussing the propogation delay aspect of
the question, but the phase shift introduced by the RC filter that
results in that HF rolloff is far more significant. At frequencies
less than 1/10th that filter's corner frequency, the frequency at
which 6 dB of loss occurs, the phase shift is negligible. The shift
is 45 degrees at the corner frequency and grows to nearly 90 degrees
at frequencies about 10 times the corner frequency.

Depending on the signal's source impedance and the cable's capacitance,
then, relatively short cables can result in appreciable phase shift.

--
================================================== ======================
Michael Kesti | "And like, one and one don't make
| two, one and one make one."
| - The Who, Bargain


  #11   Report Post  
Chris Hornbeck
 
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Default cable length needed to create phase shift?

On Fri, 31 Oct 2003 01:33:35 GMT,
(Ben Bradley) wrote:

I recall a "billiard" but I forget where it
goes in the sequence.


It's equal to 10 ^ 3 snookers.

Chris Hornbeck
new email address
  #12   Report Post  
Patrick
 
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Default cable length needed to create phase shift?

thanks for all the replies, definitely a good double-check to my math!
  #13   Report Post  
Pooh Bear
 
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Default cable length needed to create phase shift?

Patrick wrote:

how much of a difference in cable length would it take to create a
noticeable phase difference between two signals coming from the same
source simultaneously? i.e., wouldn't a 1000' xlr cable arrive at the
pre, recorder, etc. much later than the signal that only had to travel
through a 25' xlr cable?


A few picoseconds / nanoseconds later, as a guess, without getting the
calculator out.

In days of old, TV studios with multiple cameras used drums of cable to
delay the signal from some cameras, so that all of them were precisely
synched.

If your worried about time delays ( not actually phase shift ) , worry
about the different processing time in digital desks !

E.g. - if you patch in a compressor algorithm, the extra instructions
required will delay the signal by 'X' number of CPU cycles.


Graham

  #14   Report Post  
William Sommerwerck
 
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Default cable length needed to create phase shift?

The signal travels at close to the speed of light. Assume it's really slow (say,
half) and figure it out yourself.

Don't the schools teach math any more?

how much of a difference in cable length would it take to create a
noticeable phase difference between two signals coming from the
same source simultaneously? ie, wouldn't a 1000' xlr cable arrive
at the pre, recorder, etc. much later than the signal that only had to
travel through a 25' xlr cable?


  #15   Report Post  
William Sommerwerck
 
Posts: n/a
Default cable length needed to create phase shift?

At the velocity electrons travel in metal (nearly 186,000 miles/sec or
almost a trillion (10^9) feet/sec), that length difference wouldn't matter.


Actually, electrons travel very slowly in metal -- a fraction of an inch per
second, IIRC.



  #16   Report Post  
Mike Turk
 
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Default cable length needed to create phase shift?


"William Sommerwerck" wrote in message
...
At the velocity electrons travel in metal (nearly 186,000 miles/sec or
almost a trillion (10^9) feet/sec), that length difference wouldn't

matter.

Actually, electrons travel very slowly in metal -- a fraction of an inch

per
second, IIRC.


Hmmnn ... that might be interesting .... a CD player might be done playing
the CD before you heard any music coming out of the speakers! g

-mike


  #17   Report Post  
Arny Krueger
 
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Default cable length needed to create phase shift?

"Michael R. Kesti" wrote in message

Ben Bradley wrote:

snip

What could be a real problem with 1000 feet of cable is high
frequency rolloff due to the capacitance of the cable.


Hmmm... Everybody's been discussing the propogation delay aspect of
the question, but the phase shift introduced by the RC filter that
results in that HF rolloff is far more significant. At frequencies
less than 1/10th that filter's corner frequency, the frequency at
which 6 dB of loss occurs, the phase shift is negligible. The shift
is 45 degrees at the corner frequency and grows to nearly 90 degrees
at frequencies about 10 times the corner frequency.

Depending on the signal's source impedance and the cable's
capacitance, then, relatively short cables can result in appreciable
phase shift.


Yes, but there are frequency response losses associated with delay obtained
this way. Most people who say they are looking for phase shift are looking
for phase shift without frequency response losses. If moderate amounts of
delay are desired, all-pass networks can be a solution for this requirement.
If more delay is desired, then digital delays can be good and priced
reasonably. However, all such delay must be causal - IOW the delay has a
positive amount of time associated with it.

In a DAW environment practically arbitrary amounts of what, from the
viewpoint of the recording amounts to be causal or acausal delay are
basically *free*.


  #18   Report Post  
Rob Adelman
 
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Default cable length needed to create phase shift?



William Sommerwerck wrote:
At the velocity electrons travel in metal (nearly 186,000 miles/sec or
almost a trillion (10^9) feet/sec), that length difference wouldn't matter.



Actually, electrons travel very slowly in metal -- a fraction of an inch per
second, IIRC.


But doesn't each electron just bump the next one into submission? Kind
of like a relay race?

  #19   Report Post  
Michael R. Kesti
 
Posts: n/a
Default cable length needed to create phase shift?

Rob Adelman wrote:

William Sommerwerck wrote:
At the velocity electrons travel in metal (nearly 186,000 miles/sec or
almost a trillion (10^9) feet/sec), that length difference wouldn't matter.



Actually, electrons travel very slowly in metal -- a fraction of an inch per
second, IIRC.


But doesn't each electron just bump the next one into submission? Kind
of like a relay race?


Yes. Think of a hose filled with marbles. Push one more marble in at one
end and a marble falls out the other end almost instantaneously. The net
velocity of the individual marbles, however, is relatively low.

--
================================================== ======================
Michael Kesti | "And like, one and one don't make
| two, one and one make one."
| - The Who, Bargain
  #20   Report Post  
Scott Dorsey
 
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Default cable length needed to create phase shift?

In article .rogers.com,
Mike Turk wrote:

"William Sommerwerck" wrote in message
...
At the velocity electrons travel in metal (nearly 186,000 miles/sec or
almost a trillion (10^9) feet/sec), that length difference wouldn't

matter.

Actually, electrons travel very slowly in metal -- a fraction of an inch

per
second, IIRC.


Hmmnn ... that might be interesting .... a CD player might be done playing
the CD before you heard any music coming out of the speakers! g


No, the wave travels at a good fraction of the speed of light, but the
electrons themselves travel much more slowly.

Imagine a row of ping pong balls. You tap one, and it taps the next one,
and the ball at the end of the row wiggles very quickly after the taps. But
it takes an awful lot of tapping before the next-to-last ball is moved into
the last ball position. The electrons move slowly, the wave travels quickly.
--scott

--
"C'est un Nagra. C'est suisse, et tres, tres precis."


  #21   Report Post  
Jay Kadis
 
Posts: n/a
Default cable length needed to create phase shift?

In article "William Sommerwerck"
writes:
At the velocity electrons travel in metal (nearly 186,000 miles/sec or
almost a trillion (10^9) feet/sec), that length difference wouldn't matter.


Actually, electrons travel very slowly in metal -- a fraction of an inch per
second, IIRC.


As individual electrons, yes, but they force their neighbors to move and the
net effect is a flow at a decent fraction of the velocity of light.

-Jay
--
x------- Jay Kadis ------- x---- Jay's Attic Studio ----x
x Lecturer, Audio Engineer x Dexter Records x
x CCRMA, Stanford University x http://www.offbeats.com/ x
x-------- http://ccrma-www.stanford.edu/~jay/ ----------x
  #24   Report Post  
Roger W. Norman
 
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Default cable length needed to create phase shift?

How come everyone griped with Stephan Paul brought this up? g

--


Roger W. Norman
SirMusic Studio
Purchase your copy of the Fifth of RAP CD set at www.recaudiopro.net.
See how far $20 really goes.




"Scott Dorsey" wrote in message
...
In article .rogers.com,
Mike Turk wrote:

"William Sommerwerck" wrote in message
...
At the velocity electrons travel in metal (nearly 186,000 miles/sec

or
almost a trillion (10^9) feet/sec), that length difference wouldn't

matter.

Actually, electrons travel very slowly in metal -- a fraction of an

inch
per
second, IIRC.


Hmmnn ... that might be interesting .... a CD player might be done

playing
the CD before you heard any music coming out of the speakers! g


No, the wave travels at a good fraction of the speed of light, but the
electrons themselves travel much more slowly.

Imagine a row of ping pong balls. You tap one, and it taps the next one,
and the ball at the end of the row wiggles very quickly after the taps.

But
it takes an awful lot of tapping before the next-to-last ball is moved

into
the last ball position. The electrons move slowly, the wave travels

quickly.
--scott

--
"C'est un Nagra. C'est suisse, et tres, tres precis."



  #25   Report Post  
Kurt Albershardt
 
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Default cable length needed to create phase shift?

Mike Rivers wrote:

What's curious is that people worry about phase shift caused by cables
in a studio.


It sure made a difference in analog TV...






  #26   Report Post  
S O'Neill
 
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Default cable length needed to create phase shift?

Kurt Albershardt wrote:

Mike Rivers wrote:


What's curious is that people worry about phase shift caused by cables
in a studio.



It sure made a difference in analog TV...


....because the frequencies are about 1000 times as high, so the
distances are about 1000x less.

  #27   Report Post  
Michael R. Kesti
 
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Default cable length needed to create phase shift?

Kurt Albershardt wrote:

Mike Rivers wrote:

What's curious is that people worry about phase shift caused by cables
in a studio.


It sure made a difference in analog TV...


I suppose that this may explain why some people concern themselves about it
in audio, but it's very much an apples and oranges comparison.

First, the frequencies involved in analog video are much higher and it
therefore takes much less cable length to generate specific amounts of shift.

Second, the phase shifts that result from propogation delay in analog video
cables result in color changes to which human eyes are very sensitive. A
shift of just one degree at color shubcarrier (3.58 MHz in NTSC) can be
easily detected. The human ear, on the other hand, is all but deaf to audio
phase shifts. For most people, such shifts become detectable only when the
unshifted and shifted signals are mixed and then only when shifts of tens
of degrees occur.

--
================================================== ======================
Michael Kesti | "And like, one and one don't make
| two, one and one make one."
| - The Who, Bargain
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