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#1
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chung wrote:
S888Wheel wrote: From: chung Date: 6/17/2004 3:29 PM Pacific Standard Time Message-id: S888Wheel wrote: And, too, a measurable difference is not necessarily audible. Never said it was. However if there is no measurable differences between two signals then there is nothing to discuss. They will make the same sound with the same associated equipment. The problem, of course, is that usually there is a measureable difference between two components, since our measuring instruments are so sensitive. It is not a problem for the instances in which there is no measurable differrence. My point is that there are very few instances where there is no measureable difference, because of the sensitivity of our test instruments. Care to provide examples where differences are not measureable? I would offer as an example bit-identity of two .wav files....which has not prevented listeners from claiming that they still sound different. In fact, what has happened in that case is lots of time spent trying to find a *differnt* measurement to validate the supposed difference (with 'jitter' usually named, but AFAIK never proved to be, the culprit). -- -S. Why don't you just admit that you hate music and leave people alone. -- spiffy |
#2
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Steven Sullivan wrote:
chung wrote: S888Wheel wrote: From: chung Date: 6/17/2004 3:29 PM Pacific Standard Time Message-id: S888Wheel wrote: And, too, a measurable difference is not necessarily audible. Never said it was. However if there is no measurable differences between two signals then there is nothing to discuss. They will make the same sound with the same associated equipment. The problem, of course, is that usually there is a measureable difference between two components, since our measuring instruments are so sensitive. It is not a problem for the instances in which there is no measurable differrence. My point is that there are very few instances where there is no measureable difference, because of the sensitivity of our test instruments. Care to provide examples where differences are not measureable? I would offer as an example bit-identity of two .wav files....which has not prevented listeners from claiming that they still sound different. In fact, what has happened in that case is lots of time spent trying to find a *differnt* measurement to validate the supposed difference (with 'jitter' usually named, but AFAIK never proved to be, the culprit). Yes, this is one of the few cases where you can measure no difference, but that's between 2 CD's and probably not what audiophiles were thinking of measuring. And there is speculation that bit-identical CD's may still sound different due to jitter. |
#3
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#5
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chung wrote:
Bromo wrote: On 6/18/04 9:42 PM, in article , "chung" wrote: I would offer as an example bit-identity of two .wav files....which has not prevented listeners from claiming that they still sound different. In fact, what has happened in that case is lots of time spent trying to find a *differnt* measurement to validate the supposed difference (with 'jitter' usually named, but AFAIK never proved to be, the culprit). Yes, this is one of the few cases where you can measure no difference, but that's between 2 CD's and probably not what audiophiles were thinking of measuring. And there is speculation that bit-identical CD's may still sound different due to jitter. If there is one transport that produces high jitter and one that produces low jitter - they will sound different. But it is measurable. No, I was talking about the same CD player/transport/DAC. If I understand correclty, the hypothesis inherent CD jitter (versus playback path jitter), is that two bit-identical CDs can be different because one was manufactured with more jitter than the other. If so, one thing I'm not clear on is, why doesn't such jitter show up in comparison of the 'bits'? -- -S. Why don't you just admit that you hate music and leave people alone. -- spiffy |
#6
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Steven Sullivan wrote:
chung wrote: Bromo wrote: On 6/18/04 9:42 PM, in article , "chung" wrote: I would offer as an example bit-identity of two .wav files....which has not prevented listeners from claiming that they still sound different. In fact, what has happened in that case is lots of time spent trying to find a *differnt* measurement to validate the supposed difference (with 'jitter' usually named, but AFAIK never proved to be, the culprit). Yes, this is one of the few cases where you can measure no difference, but that's between 2 CD's and probably not what audiophiles were thinking of measuring. And there is speculation that bit-identical CD's may still sound different due to jitter. If there is one transport that produces high jitter and one that produces low jitter - they will sound different. But it is measurable. No, I was talking about the same CD player/transport/DAC. If I understand correclty, the hypothesis inherent CD jitter (versus playback path jitter), is that two bit-identical CDs can be different because one was manufactured with more jitter than the other. If so, one thing I'm not clear on is, why doesn't such jitter show up in comparison of the 'bits'? I have read that the same music CD made from masters cut from different machines can sound different, according to tests done at Sony Music. The data is the same, and the error rate is low. My guess is that a given CD player's output jitter may be a function of the physical "wobbliness" or concentricities of the tracks. And a good CD player/DAC should be able to reject this jitter, but perhaps some players/DAC's do not do a very good job of this. The data is still bit perfect. So if you use a good digital audio extraction program, you will still have bit-perfect data. However, when the CD is being played in real time, jitter, which is basically noise in the frequency of the DAC clock, can be affected if the servo circuitry has a tougher time tracking the lands and pits. |
#7
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In article , chung
wrote: The data is still bit perfect. So if you use a good digital audio extraction program, you will still have bit-perfect data. However, when the CD is being played in real time, jitter, which is basically noise in the frequency of the DAC clock, can be affected if the servo circuitry has a tougher time tracking the lands and pits. Can theoretically be affected. I don't think I've ever seen anything establishing a concrete link, just speculation about extra servo "circuit" noise being coupled into something else. ("Circuit" in quotes because the servo system here is likely to be a bit of extra DSP software.) If there is a real effect along those lines, jitter in the playback clock does not seem likely -- plain old noise coupling into the DAC output is a far more realistic scenario. Any change in the digital portion of the system is unlikely since digital circuits are highly resistant to noise. Not that I think noise coupling into the analog section is a likely scenario either. Servo corrections happen all the time even when there aren't problems with the disc -- otherwise it wouldn't be necessary to have servos. By far the most likely scenario in which nominally bit identical discs play back different is when they don't actually read back bit identical, i.e. one or both of the "identical" discs has recording problems serious enough to sometimes result in uncorrectable errors during playback. -- Tim |
#8
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chung wrote:
Steven Sullivan wrote: chung wrote: S888Wheel wrote: From: chung Date: 6/17/2004 3:29 PM Pacific Standard Time Message-id: S888Wheel wrote: And, too, a measurable difference is not necessarily audible. Never said it was. However if there is no measurable differences between two signals then there is nothing to discuss. They will make the same sound with the same associated equipment. The problem, of course, is that usually there is a measureable difference between two components, since our measuring instruments are so sensitive. It is not a problem for the instances in which there is no measurable differrence. My point is that there are very few instances where there is no measureable difference, because of the sensitivity of our test instruments. Care to provide examples where differences are not measureable? I would offer as an example bit-identity of two .wav files....which has not prevented listeners from claiming that they still sound different. In fact, what has happened in that case is lots of time spent trying to find a *differnt* measurement to validate the supposed difference (with 'jitter' usually named, but AFAIK never proved to be, the culprit). Yes, this is one of the few cases where you can measure no difference, but that's between 2 CD's and probably not what audiophiles were thinking of measuring. Audiophiles have played a significant part in driving the whole 'bit identical CDs sound different' goose chase. As a result we have pseudoscientific websites such as: http://www.altmann.haan.de/jitter/en...ngc_navfr.html where, after pages of technical discussion of jitter, interlaced with qyestionable claims of audibility, we are presented with evidence.... from sighted comparison. -- -S. Why don't you just admit that you hate music and leave people alone. -- spiffy |
#9
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Wow, they got total satisfaction policy, so I might give it a try. Not many
guys do that. "Steven Sullivan" wrote in message ... chung wrote: Audiophiles have played a significant part in driving the whole 'bit identical CDs sound different' goose chase. As a result we have pseudoscientific websites such as: http://www.altmann.haan.de/jitter/en...ngc_navfr.html where, after pages of technical discussion of jitter, interlaced with qyestionable claims of audibility, we are presented with evidence.... from sighted comparison. -- -S. Why don't you just admit that you hate music and leave people alone. -- spiffy |
#10
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"Chelvam" wrote in
news:rI_Ac.76602$0y.9306@attbi_s03: Wow, they got total satisfaction policy, so I might give it a try. Not many guys do that. Satisfaction guarantees are not proof of anything. Here is a quote from that particular website. "There are several jitter attenuation or reclocking products on the market. All of these products suffer from the fact, that you need a cable, in order to connect to the digital receiver (f.e. DA converter). This will introduce new jitter, the cleaned signal will be contaminated again, before it reaches the receiving device." How is jitter reintroduced with a short cable yet digitized telephone signals travel over miles of copper without impact? IOW, that site could be deconstructed quite easily, but isn't worth the time, bandwidth, nor the effort. r -- Nothing beats the bandwidth of a station wagon filled with DLT tapes. |
#11
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IF you got through other posts here, especailly the one on Vintage DAC-
jitter is a higher in separate DAC. ___ "Rich.Andrews" wrote in message news ![]() How is jitter reintroduced with a short cable yet digitized telephone signals travel over miles of copper without impact? IOW, that site could be deconstructed quite easily, but isn't worth the time, bandwidth, nor the effort. r -- Nothing beats the bandwidth of a station wagon filled with DLT tapes. |
#12
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It is all in the digital receiver - and the amount of allowable timing
errors before it turns into audible errors. The higher the "oversampling" or "sampling" rate, the better the clock recovery has to be - and the less room for error. In a digitized telephone network the allowable timing errors and dispersion allowed is helped with the limited bandwidth, and the recovery circuits are quite good. On 6/20/04 10:30 AM, in article , "Chelvam" wrote: IF you got through other posts here, especailly the one on Vintage DAC- jitter is a higher in separate DAC. ___ "Rich.Andrews" wrote in message news ![]() How is jitter reintroduced with a short cable yet digitized telephone signals travel over miles of copper without impact? IOW, that site could be deconstructed quite easily, but isn't worth the time, bandwidth, nor the effort. r -- Nothing beats the bandwidth of a station wagon filled with DLT tapes. |
#13
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On 6/19/04 11:05 PM, in article oa7Bc.72457$eu.43358@attbi_s02,
"Rich.Andrews" wrote: "Chelvam" wrote in news:rI_Ac.76602$0y.9306@attbi_s03: Wow, they got total satisfaction policy, so I might give it a try. Not many guys do that. Satisfaction guarantees are not proof of anything. Here is a quote from that particular website. "There are several jitter attenuation or reclocking products on the market. All of these products suffer from the fact, that you need a cable, in order to connect to the digital receiver (f.e. DA converter). This will introduce new jitter, the cleaned signal will be contaminated again, before it reaches the receiving device." How is jitter reintroduced with a short cable yet digitized telephone signals travel over miles of copper without impact? IOW, that site could be deconstructed quite easily, but isn't worth the time, bandwidth, nor the effort. If you don't - the other guys will win. |
#14
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Bromo wrote in news:VbjBc.148836$Ly.4255@attbi_s01:
IOW, that site could be deconstructed quite easily, but isn't worth the time, bandwidth, nor the effort. If you don't - the other guys will win. I did not realize it was about "winning". It is quite obvious that the information given on the web pages in question, is false. There is no point in discussing that web site any further. Magic pixie dust may sound like a great way to fix problems, but truth be told, magic pixie dust does not exist. r -- Nothing beats the bandwidth of a station wagon filled with DLT tapes. |