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#81
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The problem is that if it is not a VOLTAGE change, but an increase in
AMPERAGE, your test is worthless. Remember, more amperage = better bass as much, if not more than higher voltage. Potential without anything to actualize that potential is worthless. Once you add any device to read the current, you may very well be effecting the previous stage of amplification with your load/meter. Get it now? -- Best Regards, Lou "chung" wrote in message ... Lou wrote: Just how would you measure it, put in a trap, then jam in an amp meter? I don't think there is a truly passive way to measure current is there? As we are talking a specific freq range you would also have to filter it out of, then back into the rest of the signal, that should result in a time delay as well I should think. I would think it would be rather hard to do.... The voltage you ought to be able to see on a spectrum analyzer, but volts w/o current give you potential w/o action, though we are often feeding very high impedance loads when dealing with interconnects. Anyway, I would think it might be more difficult to measure than you might imagine and as I doubt there is a truly non-loading method, you will not only be driving one load, but two or more, which may overload the source making measurements impossible... Hmmm, you have been doing all these mods, and you don't know how to measure the bass response of a cable? Sweep a sinusoidal signal in frequency, and measure the voltage across the load, whether it is a speaker or a passive load. Compare the two cables' repsonse over the full frequency range. What's the problem? -- Best Regards, Lou "chung" wrote in message news:Y_fsb.128537$ao4.399503@attbi_s51... fandango wrote: snip.. I get a kick out of the people in this forum who argue that everything sounds alike--makes me wonder why they bother signing on here. :-) Can you tell us who those people are? snip... My experience tells me that there are indeed differences in the sound of some components, some of which are musically significant, and some of which matter to me, since they align with my positive emotional reactions and my listening preferences. You mean differences that align with your negative emotional reactions do not matter to you? Can you give examples of differences that align with your negative emotional reactions? I also have found that there is not always a correlation between a component's cost and how much its sound appeals to me. For example, I recently listened to a Tara Labs interconnect which had a list price of $1600/meter. I compared it to a similar length of DNM wire with Eichmann bullet plugs, and the latter presented much more detail and more realistic harmonic structure, although not as much bass. How does a cable give more or less bass? Shouldn't that be measurable, and if so, how come no one ever reported it? It's your money--listen, trust your ears, and make your purchases accordingly. And remember: it's supposed to be fun! That's a part of the "high end" we often forget about. Vade Forrester |
#82
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On 14 Nov 2003 21:59:30 GMT, "Lou" wrote:
The problem is that if it is not a VOLTAGE change, but an increase in AMPERAGE, your test is worthless. Remember, more amperage = better bass as much, if not more than higher voltage. Potential without anything to actualize that potential is worthless. Once you add any device to read the current, you may very well be effecting the previous stage of amplification with your load/meter. Get it now? It's perfectly simple to measure speaker current - you just put a 0.1 ohm resistor in series with the load, and measure the voltage across that resistor. If you think that this will somehow interfere with the speaker system or the cable, then you are really stretching. Basically, just use a cable with less than quarter of an ohm loop resistance, and you won't have any problems. Cable sound is a myth, so that's one less thing to worry about! :-) -- Stewart Pinkerton | Music is Art - Audio is Engineering |
#83
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Lou wrote:
The problem is that if it is not a VOLTAGE change, but an increase in AMPERAGE, your test is worthless. Remember, more amperage = better bass as much, if not more than higher voltage. Potential without anything to actualize that potential is worthless. Once you add any device to read the current, you may very well be effecting the previous stage of amplification with your load/meter. Get it now? Can you explain how the "amperage" could change without a corresponding change in voltage across the speaker or passive load? Still don't get it, and I have been an EE since 1976. -- Best Regards, Lou "chung" wrote in message ... Lou wrote: Just how would you measure it, put in a trap, then jam in an amp meter? I don't think there is a truly passive way to measure current is there? As we are talking a specific freq range you would also have to filter it out of, then back into the rest of the signal, that should result in a time delay as well I should think. I would think it would be rather hard to do.... The voltage you ought to be able to see on a spectrum analyzer, but volts w/o current give you potential w/o action, though we are often feeding very high impedance loads when dealing with interconnects. Anyway, I would think it might be more difficult to measure than you might imagine and as I doubt there is a truly non-loading method, you will not only be driving one load, but two or more, which may overload the source making measurements impossible... Hmmm, you have been doing all these mods, and you don't know how to measure the bass response of a cable? Sweep a sinusoidal signal in frequency, and measure the voltage across the load, whether it is a speaker or a passive load. Compare the two cables' repsonse over the full frequency range. What's the problem? -- Best Regards, Lou "chung" wrote in message news:Y_fsb.128537$ao4.399503@attbi_s51... fandango wrote: snip.. I get a kick out of the people in this forum who argue that everything sounds alike--makes me wonder why they bother signing on here. :-) Can you tell us who those people are? snip... My experience tells me that there are indeed differences in the sound of some components, some of which are musically significant, and some of which matter to me, since they align with my positive emotional reactions and my listening preferences. You mean differences that align with your negative emotional reactions do not matter to you? Can you give examples of differences that align with your negative emotional reactions? I also have found that there is not always a correlation between a component's cost and how much its sound appeals to me. For example, I recently listened to a Tara Labs interconnect which had a list price of $1600/meter. I compared it to a similar length of DNM wire with Eichmann bullet plugs, and the latter presented much more detail and more realistic harmonic structure, although not as much bass. How does a cable give more or less bass? Shouldn't that be measurable, and if so, how come no one ever reported it? It's your money--listen, trust your ears, and make your purchases accordingly. And remember: it's supposed to be fun! That's a part of the "high end" we often forget about. Vade Forrester |
#84
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#85
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Mkuller wrote:
. (Stewart Pinkerton) wrote: Cable sound is a myth, so that's one less thing to worry about! :-) With cable sound a myth, all competent amps and CD players sounding the same, that leaves little in audio for you to worry about. "What me worry?" A. E. Neuman Now if only we could get those pesky loudspeakers and rooms to sound the same. -- -S. "They've got God on their side. All we've got is science and reason." -- Dawn Hulsey, Talent Director |
#86
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Mkuller wrote:
. (Stewart Pinkerton) wrote: Cable sound is a myth, so that's one less thing to worry about! :-) With cable sound a myth, all competent amps and CD players sounding the same, that leaves little in audio for you to worry about. Why would anyone want something in audio to worry about? Just enjoy the music! "What me worry?" A. E. Neuman Regards, Mike |
#88
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Voltage is determined by the amp, though the load can cause a drop in the
voltage it should not be much of one. The current depends not upon the amp, but the load, if the speakers want more current to move a lower frequency, due to further excursion of the driver, then it will demand more current, though not more voltage as it cannot demand voltage, from the source. I work with a LOT of EE types, it does not mean they understand electronics, the ones I work with know PLC's, 4-20 loops PID loops, etc, but not electronics. That is why I often find myself correcting them on this very issue. It is not that they are stupid, it is just that this is not their area of expertise. -- Best Regards, Lou "chung" wrote in message news:zNutb.160316$9E1.803392@attbi_s52... Lou wrote: The problem is that if it is not a VOLTAGE change, but an increase in AMPERAGE, your test is worthless. Remember, more amperage = better bass as much, if not more than higher voltage. Potential without anything to actualize that potential is worthless. Once you add any device to read the current, you may very well be effecting the previous stage of amplification with your load/meter. Get it now? Can you explain how the "amperage" could change without a corresponding change in voltage across the speaker or passive load? Still don't get it, and I have been an EE since 1976. -- Best Regards, Lou "chung" wrote in message ... Lou wrote: Just how would you measure it, put in a trap, then jam in an amp meter? I don't think there is a truly passive way to measure current is there? As we are talking a specific freq range you would also have to filter it out of, then back into the rest of the signal, that should result in a time delay as well I should think. I would think it would be rather hard to do.... The voltage you ought to be able to see on a spectrum analyzer, but volts w/o current give you potential w/o action, though we are often feeding very high impedance loads when dealing with interconnects. Anyway, I would think it might be more difficult to measure than you might imagine and as I doubt there is a truly non-loading method, you will not only be driving one load, but two or more, which may overload the source making measurements impossible... Hmmm, you have been doing all these mods, and you don't know how to measure the bass response of a cable? Sweep a sinusoidal signal in frequency, and measure the voltage across the load, whether it is a speaker or a passive load. Compare the two cables' repsonse over the full frequency range. What's the problem? -- Best Regards, Lou "chung" wrote in message news:Y_fsb.128537$ao4.399503@attbi_s51... fandango wrote: snip.. I get a kick out of the people in this forum who argue that everything sounds alike--makes me wonder why they bother signing on here. :-) Can you tell us who those people are? snip... My experience tells me that there are indeed differences in the sound of some components, some of which are musically significant, and some of which matter to me, since they align with my positive emotional reactions and my listening preferences. You mean differences that align with your negative emotional reactions do not matter to you? Can you give examples of differences that align with your negative emotional reactions? I also have found that there is not always a correlation between a component's cost and how much its sound appeals to me. For example, I recently listened to a Tara Labs interconnect which had a list price of $1600/meter. I compared it to a similar length of DNM wire with Eichmann bullet plugs, and the latter presented much more detail and more realistic harmonic structure, although not as much bass. How does a cable give more or less bass? Shouldn't that be measurable, and if so, how come no one ever reported it? It's your money--listen, trust your ears, and make your purchases accordingly. And remember: it's supposed to be fun! That's a part of the "high end" we often forget about. Vade Forrester |
#89
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On 16 Nov 2003 17:53:02 GMT, "Lou" wrote:
Voltage is determined by the amp, though the load can cause a drop in the voltage it should not be much of one. The current depends not upon the amp, but the load, if the speakers want more current to move a lower frequency, due to further excursion of the driver, then it will demand more current, though not more voltage as it cannot demand voltage, from the source. No, you misunderstand the basics here, as the *impedance* of the load will vary dramatically in the bass region, thereby affecting how much power is required for a given SPL. It is therefore a moot point whether the load will require more amps or more volts at any particular frequency. I work with a LOT of EE types, it does not mean they understand electronics, the ones I work with know PLC's, 4-20 loops PID loops, etc, but not electronics. That is why I often find myself correcting them on this very issue. It is not that they are stupid, it is just that this is not their area of expertise. Excuse me, but if they are registered professional *engineers*, they certainly *should* know electronics. You seem to be describing C&I technicians, which is a different matter entirely. -- Stewart Pinkerton | Music is Art - Audio is Engineering |
#90
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chung wrote:
Mkuller wrote: . (Stewart Pinkerton) wrote: Cable sound is a myth, so that's one less thing to worry about! :-) With cable sound a myth, all competent amps and CD players sounding the same, that leaves little in audio for you to worry about. Why would anyone want something in audio to worry about? Just enjoy the music! Simple. Audiophiles don't really like music, they just like the sound of it. |
#91
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Lou wrote:
Voltage is determined by the amp, though the load can cause a drop in the voltage it should not be much of one. The current depends not upon the amp, but the load, if the speakers want more current to move a lower frequency, due to further excursion of the driver, then it will demand more current, though not more voltage as it cannot demand voltage, from the source. I work with a LOT of EE types, it does not mean they understand electronics, the ones I work with know PLC's, 4-20 loops PID loops, etc, but not electronics. That is why I often find myself correcting them on this very issue. So, you worked with some EE's and by your standards, they don't understand electronics the way you do. Were you "correcting them" or did you understand what they are saying? It is not that they are stupid, it is just that this is not their area of expertise. This is really as simple as applying Ohm's law. The amp can be modelled as a voltage source with a small resistance. The cable is connected between amp and load. You measure the voltage across the load, over the bass frequency range of interest. If one cable has "more" bass response, the voltage across the load will be higher than that for the other cable. Use resistive loads to simplify things in your mind. Also compare at 1 KHz to take out the resistive effects of the cable due to length. Now, can you do what I asked, which is to explain how voltages across the load can stay the same if the current (or amperage as you called it) change? In DBT's of cables, it is standard fare to match response to within 0.1 dB. So people have done that all the time. In fact, seldom would they look at response at the bass end, since that is totally dependent on the length (i.e. the series resistance), and not on capacitance or inductance. -- Best Regards, Lou |
#92
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Lou wrote:
I work with a LOT of EE types, it does not mean they understand electronics, the ones I work with know PLC's, 4-20 loops PID loops, etc, but not electronics. That is why I often find myself correcting them on this very issue. It is not that they are stupid, it is just that this is not their area of expertise. Or they just forgot. This theory is taught universally in an EE undergraduate program around the second or third year - a first course in electronics or circuit theory. The concepts of ideal voltage source, ideal current source, etc. usually come at about the same time as Thevenin equivalent circuits. Even a "sub-standard" school like DeVry taught us that. --A DeVry Graduate (as well as a EE and Mathematics graduate from the University of South Florida). -- % Randy Yates % "...the answer lies within your soul %% Fuquay-Varina, NC % 'cause no one knows which side %%% 919-577-9882 % the coin will fall." %%%% % 'Big Wheels', *Out of the Blue*, ELO http://home.earthlink.net/~yatescr |
#93
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wrote in message ...
chung wrote: Mkuller wrote: . (Stewart Pinkerton) wrote: Cable sound is a myth, so that's one less thing to worry about! :-) With cable sound a myth, all competent amps and CD players sounding the same, that leaves little in audio for you to worry about. Why would anyone want something in audio to worry about? Just enjoy the music! Simple. Audiophiles don't really like music, they just like the sound of it. It must be nice to know that you can speak for all audiophiles. Such certainty. I hate to shatter your fantasies. But my interest in music preceded my interest in equipment. First and foremost because I love jazz, having been raised in a household full of it (my dad was a jazz drummer in his early years). My best friends since college have been a couple who founded a successful (for 27 years) professional chamber group, and I have attended hundreds of chamber concerts over the years. It is my favorite type of music other than jazz. In addition, I was a chorister in high school and have a real fondness for choral music. I guess I don't qualify as an audiophile then, right? |
#94
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They have letters from men, they are engineers. I know not if they are
"registered" what ever that means. Not much emphasis seems to be placed upon analogue these days in the schools, or at least that is what they tell me. " No, you misunderstand the basics here, as the *impedance* of the load will vary dramatically in the bass region, thereby affecting how much power is required for a given SPL. It is therefore a moot point whether the load will require more amps or more volts at any particular frequency." Someone sure is misunderstanding someone here... If you claim that an IC gives you more bass, sure you can compare the current in the 2 ICs, but the only way to know would be to filter out the low frequencies where it is said they are hearing more bass, and see if there is in fact more current flow there. -- Best Regards, Lou "Stewart Pinkerton" wrote in message ... On 16 Nov 2003 17:53:02 GMT, "Lou" wrote: Voltage is determined by the amp, though the load can cause a drop in the voltage it should not be much of one. The current depends not upon the amp, but the load, if the speakers want more current to move a lower frequency, due to further excursion of the driver, then it will demand more current, though not more voltage as it cannot demand voltage, from the source. No, you misunderstand the basics here, as the *impedance* of the load will vary dramatically in the bass region, thereby affecting how much power is required for a given SPL. It is therefore a moot point whether the load will require more amps or more volts at any particular frequency. I work with a LOT of EE types, it does not mean they understand electronics, the ones I work with know PLC's, 4-20 loops PID loops, etc, but not electronics. That is why I often find myself correcting them on this very issue. It is not that they are stupid, it is just that this is not their area of expertise. Excuse me, but if they are registered professional *engineers*, they certainly *should* know electronics. You seem to be describing C&I technicians, which is a different matter entirely. -- Stewart Pinkerton | Music is Art - Audio is Engineering |
#95
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Lou wrote:
They have letters from men, they are engineers. I know not if they are "registered" what ever that means. Not much emphasis seems to be placed upon analogue these days in the schools, or at least that is what they tell me. " No, you misunderstand the basics here, as the *impedance* of the load will vary dramatically in the bass region, thereby affecting how much power is required for a given SPL. It is therefore a moot point whether the load will require more amps or more volts at any particular frequency." Someone sure is misunderstanding someone here... If you claim that an IC gives you more bass, sure you can compare the current in the 2 ICs, but the only way to know would be to filter out the low frequencies where it is said they are hearing more bass, and see if there is in fact more current flow there. For there to be "more current flow" with one cable, there has to be more voltage measured across the load. Why is this difficult to see? Are you saying that there can be more current flowing into the load with the *same* measured voltage across the load? Does "impedance" mean anything to you? You realize that we are not comparing speakers. We are talking about differences in bass response between two cables. -- |
#96
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All CDPs and amps SHOULD sound the same, but they hardly do... Compare a
Sony DVP-S9000ES against anything you can get at Wal-Mart... -- Best Regards, Lou "Mkuller" wrote in message news:5cxtb.157598$mZ5.1081553@attbi_s54... . (Stewart Pinkerton) wrote: Cable sound is a myth, so that's one less thing to worry about! :-) With cable sound a myth, all competent amps and CD players sounding the same, that leaves little in audio for you to worry about. "What me worry?" A. E. Neuman Regards, Mike |
#97
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Hi Randy,
Exactly, I use it slightly more than they do, so it stays a little fresher in my memory, though I am admittedly pretty rusty myself. Industrial repair pays a heck of a lot more than electronic repair... -- Best Regards, Lou "Randy Yates" wrote in message news:2p7ub.224680$Tr4.664361@attbi_s03... Lou wrote: I work with a LOT of EE types, it does not mean they understand electronics, the ones I work with know PLC's, 4-20 loops PID loops, etc, but not electronics. That is why I often find myself correcting them on this very issue. It is not that they are stupid, it is just that this is not their area of expertise. Or they just forgot. This theory is taught universally in an EE undergraduate program around the second or third year - a first course in electronics or circuit theory. The concepts of ideal voltage source, ideal current source, etc. usually come at about the same time as Thevenin equivalent circuits. Even a "sub-standard" school like DeVry taught us that. --A DeVry Graduate (as well as a EE and Mathematics graduate from the University of South Florida). -- % Randy Yates % "...the answer lies within your soul %% Fuquay-Varina, NC % 'cause no one knows which side %%% 919-577-9882 % the coin will fall." %%%% % 'Big Wheels', *Out of the Blue*, ELO http://home.earthlink.net/~yatescr |
#98
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I am not saying that I never need correcting Mr. Chung, but your implication
is insulting as you imply that I am less than honest here, be it with myself, or you, or who ever... It is not that they do not understand it as I do, or that I did not understand what they were saying as they have adopted what I said. They just do not work with electronics, they would with PLC's networking PLC's, and ladder logic, there is a difference. Use it or lose it, which is why I am not as current as I might like to be either. I nearly never do electronics outside of this hobby, meaning very rarely at work. It is far more electrical and I suppose technical in nature. This is really as simple as applying Ohm's law. The amp can be modelled as a voltage source with a small resistance. The cable is connected between amp and load. You measure the voltage across the load, over the bass frequency range of interest. If one cable has "more" bass response, the voltage across the load will be higher than that for the other cable. Use resistive loads to simplify things in your mind. Also compare at 1 KHz to take out the resistive effects of the cable due to length. You are right, I was not thinking of using a signal generator, I was thinking in terms of the entire signal. Now, can you do what I asked, which is to explain how voltages across the load can stay the same if the current (or amperage as you called it) change? What I was attempting to say was that the input signal determines the voltage, not the current. That the amp will attempt to supply the required current as determined by the load and the voltage. More percisely I was speaking of a music signal, and was speaking about one frequency, as you are dealing with a complex load, LCR as opposed to a resistive load, anything can draw current, thus an increase in current at some frequency does not mean an increase at all frequencies, as a driver will have uneven load characteristics at various frequencies. Thus an increase in over all current does not necessarily mean it is greater at a specific frequency, that that freq would have to be isolated to be sure the increase is in that range. Unfortunately I did not even think of a signal generator. In fact, seldom would they look at response at the bass end, since that is totally dependent on the length (i.e. the series resistance), and not on capacitance or inductance Thus if one cable has less resistance per foot, one would expect to hear a difference in bass? -- Best Regards, Lou "chung" wrote in message news:aiStb.19265$Dw6.88484@attbi_s02... Lou wrote: Voltage is determined by the amp, though the load can cause a drop in the voltage it should not be much of one. The current depends not upon the amp, but the load, if the speakers want more current to move a lower frequency, due to further excursion of the driver, then it will demand more current, though not more voltage as it cannot demand voltage, from the source. I work with a LOT of EE types, it does not mean they understand electronics, the ones I work with know PLC's, 4-20 loops PID loops, etc, but not electronics. That is why I often find myself correcting them on this very issue. So, you worked with some EE's and by your standards, they don't understand electronics the way you do. Were you "correcting them" or did you understand what they are saying? It is not that they are stupid, it is just that this is not their area of expertise. This is really as simple as applying Ohm's law. The amp can be modelled as a voltage source with a small resistance. The cable is connected between amp and load. You measure the voltage across the load, over the bass frequency range of interest. If one cable has "more" bass response, the voltage across the load will be higher than that for the other cable. Use resistive loads to simplify things in your mind. Also compare at 1 KHz to take out the resistive effects of the cable due to length. Now, can you do what I asked, which is to explain how voltages across the load can stay the same if the current (or amperage as you called it) change? In DBT's of cables, it is standard fare to match response to within 0.1 dB. So people have done that all the time. In fact, seldom would they look at response at the bass end, since that is totally dependent on the length (i.e. the series resistance), and not on capacitance or inductance. -- Best Regards, Lou |
#99
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Harry Lavo wrote:
It must be nice to know that you can speak for all audiophiles. Such certainty. I hate to shatter your fantasies. But my interest in music preceded my interest in equipment. First and foremost because I love jazz, having been raised in a household full of it (my dad was a jazz drummer in his early years). My best friends since college have been a couple who founded a successful (for 27 years) professional chamber group, and I have attended hundreds of chamber concerts over the years. It is my favorite type of music other than jazz. In addition, I was a chorister in high school and have a real fondness for choral music. I guess I don't qualify as an audiophile then, right? It is a half serious joke. I suppose I should have put in a 'humor alert', no? It IS true in some cases. |
#100
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Chung said;
"For there to be "more current flow" with one cable, there has to be more voltage measured across the load. Why is this difficult to see?" Drugs in my younger days, I have the flue, I really do, had a flue shot, but that was a waste. I was thinking about a music signal into a full range speaker. "Are you saying that there can be more current flowing into the load with the *same* measured voltage across the load? Does "impedance" mean anything to you?" I have already addressed this in another post, there is no need to argue it in 2 posts. You realize that we are not comparing speakers. We are talking about differences in bass response between two cables. Actually I was thinking of IC's between components more than speaker cables, once you get into a good cable, I have not tried 12 gage wire so I cannot comment, but once you get into a Goertz, Kimber, Monster, et. al. I cannot hear a difference, but I have heard differences in IC's. -- Best Regards, Lou "chung" wrote in message ... Lou wrote: They have letters from men, they are engineers. I know not if they are "registered" what ever that means. Not much emphasis seems to be placed upon analogue these days in the schools, or at least that is what they tell me. " No, you misunderstand the basics here, as the *impedance* of the load will vary dramatically in the bass region, thereby affecting how much power is required for a given SPL. It is therefore a moot point whether the load will require more amps or more volts at any particular frequency." Someone sure is misunderstanding someone here... If you claim that an IC gives you more bass, sure you can compare the current in the 2 ICs, but the only way to know would be to filter out the low frequencies where it is said they are hearing more bass, and see if there is in fact more current flow there. For there to be "more current flow" with one cable, there has to be more voltage measured across the load. Why is this difficult to see? Are you saying that there can be more current flowing into the load with the *same* measured voltage across the load? Does "impedance" mean anything to you? You realize that we are not comparing speakers. We are talking about differences in bass response between two cables. -- |
#101
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Lou wrote:
I am not saying that I never need correcting Mr. Chung, but your implication is insulting as you imply that I am less than honest here, be it with myself, or you, or who ever... OK, you were the one saying that those EE's did not know about voltages and currents. Based on the knowledge you have so far displayed here, you probably did not understand what these EE's were trying to tell you. If you think it is insulting for me to point it out, think about your statement that these EE's did not know voltages and currents like you do. Frankly, that is insulting. And honesty has nothing to do with it. It is not that they do not understand it as I do, or that I did not understand what they were saying as they have adopted what I said. They just do not work with electronics, they would with PLC's networking PLC's, and ladder logic, there is a difference. Use it or lose it, which is why I am not as current as I might like to be either. I nearly never do electronics outside of this hobby, meaning very rarely at work. It is far more electrical and I suppose technical in nature. This is really as simple as applying Ohm's law. The amp can be modelled as a voltage source with a small resistance. The cable is connected between amp and load. You measure the voltage across the load, over the bass frequency range of interest. If one cable has "more" bass response, the voltage across the load will be higher than that for the other cable. Use resistive loads to simplify things in your mind. Also compare at 1 KHz to take out the resistive effects of the cable due to length. You are right, I was not thinking of using a signal generator, I was thinking in terms of the entire signal. Well, if it takes 2 to 3 tries before you get the point, how can I take your word that those EE's did not understand stuff like you could? Now, can you do what I asked, which is to explain how voltages across the load can stay the same if the current (or amperage as you called it) change? What I was attempting to say was that the input signal determines the voltage, not the current. That the amp will attempt to supply the required current as determined by the load and the voltage. More percisely I was speaking of a music signal, and was speaking about one frequency, as you are dealing with a complex load, LCR as opposed to a resistive load, anything can draw current, thus an increase in current at some frequency does not mean an increase at all frequencies, as a driver will have uneven load characteristics at various frequencies. Thus an increase in over all current does not necessarily mean it is greater at a specific frequency, that that freq would have to be isolated to be sure the increase is in that range. Unfortunately I did not even think of a signal generator. In fact, seldom would they look at response at the bass end, since that is totally dependent on the length (i.e. the series resistance), and not on capacitance or inductance Thus if one cable has less resistance per foot, one would expect to hear a difference in bass? Absolutly no. If the cables have different *total* resistance, there will be a slight shift of the whole response, up or down. We are talking milliohms here compared to the several ohms of speaker impedance. But to imply that cable A has "more bass" than cable B, you need to show that after correcting for any shift due to resistance (which can be compensated by adjusting the volume control), the *shape* of the frequency response is different between the two cables in that cable A produces a higher voltage at the lower frequencies. -- Best Regards, Lou "chung" wrote in message news:aiStb.19265$Dw6.88484@attbi_s02... Lou wrote: Voltage is determined by the amp, though the load can cause a drop in the voltage it should not be much of one. The current depends not upon the amp, but the load, if the speakers want more current to move a lower frequency, due to further excursion of the driver, then it will demand more current, though not more voltage as it cannot demand voltage, from the source. I work with a LOT of EE types, it does not mean they understand electronics, the ones I work with know PLC's, 4-20 loops PID loops, etc, but not electronics. That is why I often find myself correcting them on this very issue. So, you worked with some EE's and by your standards, they don't understand electronics the way you do. Were you "correcting them" or did you understand what they are saying? It is not that they are stupid, it is just that this is not their area of expertise. This is really as simple as applying Ohm's law. The amp can be modelled as a voltage source with a small resistance. The cable is connected between amp and load. You measure the voltage across the load, over the bass frequency range of interest. If one cable has "more" bass response, the voltage across the load will be higher than that for the other cable. Use resistive loads to simplify things in your mind. Also compare at 1 KHz to take out the resistive effects of the cable due to length. Now, can you do what I asked, which is to explain how voltages across the load can stay the same if the current (or amperage as you called it) change? In DBT's of cables, it is standard fare to match response to within 0.1 dB. So people have done that all the time. In fact, seldom would they look at response at the bass end, since that is totally dependent on the length (i.e. the series resistance), and not on capacitance or inductance. -- Best Regards, Lou |
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On 17 Nov 2003 17:43:54 GMT, "Lou" wrote:
Stewart wrote: " No, you misunderstand the basics here, as the *impedance* of the load will vary dramatically in the bass region, thereby affecting how much power is required for a given SPL. It is therefore a moot point whether the load will require more amps or more volts at any particular frequency." Someone sure is misunderstanding someone here... If you claim that an IC gives you more bass, sure you can compare the current in the 2 ICs, but the only way to know would be to filter out the low frequencies where it is said they are hearing more bass, and see if there is in fact more current flow there. In my recent e-mail, which part of 'just use a low-frequency sine wave' did you fail to understand? This ain't rocket science! If there really were any differences, they would be *easily* measurable. The truth is, there aren't - *especially* in the bass region. -- Stewart Pinkerton | Music is Art - Audio is Engineering |
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Well, if it takes 2 to 3 tries before you get the point, how can I take
your word that those EE's did not understand stuff like you could? Fine, end of discussion! -- Best Regards, Lou "chung" wrote in message ... Lou wrote: I am not saying that I never need correcting Mr. Chung, but your implication is insulting as you imply that I am less than honest here, be it with myself, or you, or who ever... OK, you were the one saying that those EE's did not know about voltages and currents. Based on the knowledge you have so far displayed here, you probably did not understand what these EE's were trying to tell you. If you think it is insulting for me to point it out, think about your statement that these EE's did not know voltages and currents like you do. Frankly, that is insulting. And honesty has nothing to do with it. It is not that they do not understand it as I do, or that I did not understand what they were saying as they have adopted what I said. They just do not work with electronics, they would with PLC's networking PLC's, and ladder logic, there is a difference. Use it or lose it, which is why I am not as current as I might like to be either. I nearly never do electronics outside of this hobby, meaning very rarely at work. It is far more electrical and I suppose technical in nature. This is really as simple as applying Ohm's law. The amp can be modelled as a voltage source with a small resistance. The cable is connected between amp and load. You measure the voltage across the load, over the bass frequency range of interest. If one cable has "more" bass response, the voltage across the load will be higher than that for the other cable. Use resistive loads to simplify things in your mind. Also compare at 1 KHz to take out the resistive effects of the cable due to length. You are right, I was not thinking of using a signal generator, I was thinking in terms of the entire signal. Now, can you do what I asked, which is to explain how voltages across the load can stay the same if the current (or amperage as you called it) change? What I was attempting to say was that the input signal determines the voltage, not the current. That the amp will attempt to supply the required current as determined by the load and the voltage. More percisely I was speaking of a music signal, and was speaking about one frequency, as you are dealing with a complex load, LCR as opposed to a resistive load, anything can draw current, thus an increase in current at some frequency does not mean an increase at all frequencies, as a driver will have uneven load characteristics at various frequencies. Thus an increase in over all current does not necessarily mean it is greater at a specific frequency, that that freq would have to be isolated to be sure the increase is in that range. Unfortunately I did not even think of a signal generator. In fact, seldom would they look at response at the bass end, since that is totally dependent on the length (i.e. the series resistance), and not on capacitance or inductance Thus if one cable has less resistance per foot, one would expect to hear a difference in bass? Absolutly no. If the cables have different *total* resistance, there will be a slight shift of the whole response, up or down. We are talking milliohms here compared to the several ohms of speaker impedance. But to imply that cable A has "more bass" than cable B, you need to show that after correcting for any shift due to resistance (which can be compensated by adjusting the volume control), the *shape* of the frequency response is different between the two cables in that cable A produces a higher voltage at the lower frequencies. -- Best Regards, Lou "chung" wrote in message news:aiStb.19265$Dw6.88484@attbi_s02... Lou wrote: Voltage is determined by the amp, though the load can cause a drop in the voltage it should not be much of one. The current depends not upon the amp, but the load, if the speakers want more current to move a lower frequency, due to further excursion of the driver, then it will demand more current, though not more voltage as it cannot demand voltage, from the source. I work with a LOT of EE types, it does not mean they understand electronics, the ones I work with know PLC's, 4-20 loops PID loops, etc, but not electronics. That is why I often find myself correcting them on this very issue. So, you worked with some EE's and by your standards, they don't understand electronics the way you do. Were you "correcting them" or did you understand what they are saying? It is not that they are stupid, it is just that this is not their area of expertise. This is really as simple as applying Ohm's law. The amp can be modelled as a voltage source with a small resistance. The cable is connected between amp and load. You measure the voltage across the load, over the bass frequency range of interest. If one cable has "more" bass response, the voltage across the load will be higher than that for the other cable. Use resistive loads to simplify things in your mind. Also compare at 1 KHz to take out the resistive effects of the cable due to length. Now, can you do what I asked, which is to explain how voltages across the load can stay the same if the current (or amperage as you called it) change? In DBT's of cables, it is standard fare to match response to within 0.1 dB. So people have done that all the time. In fact, seldom would they look at response at the bass end, since that is totally dependent on the length (i.e. the series resistance), and not on capacitance or inductance. -- Best Regards, Lou |
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