"Dave Platt" wrote in message
...
If we assume a tuner input impedance of 4.7k (a fairly conventional
value), and 20 Hz, we'd find that a cap whose impedance equals this at
20 Hz is

C = 1 / (2*pi*20*4700)

which works out to about 1.7 uF. Using a cap of this value would
result in a rolloff of around 6 dB at 20 Hz.

Okay, by your logic... my amp (note my previous post) has an input impedence
of (I calculate) 44.634k. So using your formula

C=1/(2*pi*20*44634)

I get a value of 0.178uF. And my spec cap is 0.15. Pretty close I'd say.
My 0.22uF's that are in there should be good?