On Sat, 25 Jun 2005 18:24:43 -0400, "Robert Morein"
wrote:


"ric" wrote in message ...
Robert Morein wrote:

You can do it yourself. Take a look at
http://www.ycars.org/EFRA/Module%20C/AntDip.htm

The wavelength of 88.3 mHz is 66.88 inches. Your dipole should be 1/2
that
length: 33.5.

Hmmm...the website you give above contradicts that. It says:

1/2 WL dipole length = 468/f = 468/88.3 = 5.3 feet = 63.6 inches.

Since none of the existing FM dipoles I have are 63.6 inches long (the
longest being just under 5 feet), should I assume that is why they are
so poor in the "college" (88-90 MHz) FM band?

I'm sorry, Ric. I made a mistake.
The folded dipole is cut to 1/4 wavelength, which is why it works out to
33.5 inches for your frequency of interest.

********! 1,2,3,4. . .mistakes.

On Sat, 25 Jun 2005 23:10:02 GMT, ow
(Goofball_star_dot_etal) wrote:

On Sat, 25 Jun 2005 18:24:43 -0400, "Robert Morein"
wrote:

I'm sorry, Ric. I made a mistake.
The folded dipole is cut to 1/4 wavelength, which is why it works out to
33.5 inches for your frequency of interest.

********! 1,2,3,4. . .mistakes.


See: http://www.ee.surrey.ac.uk/Personal/...es/rodres.html