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In article ,
(John Byrns) wrote:
In article , "Ian
Iveson" wrote:
Are you completely daft or what?
That is what I have been saying. Double the voltage, and you need
double the turns. But you only need half the cross-sectional area,
so it should all fit together with the same core, give or take a
little to take account of scale effects of geometry and losses.
That has nothing to do with the original question, but going with it, if
we need twice as many turns, and each has half the cross sectional area,
doesn't that mean the copper losses for the winding, at a given power,
will double?
oops, forget it, that was wrong, that's what I get for trying to do simple
math in my head.
Regards,
John Byrns
Surf my web pages at, http://users.rcn.com/jbyrns/
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