Andy Fish wrote:
"Andy Dee" wrote in message
...

Andy Fish wrote:

Hi,

as a hi-fi owner with some background knowledge of physics but no idea

of

speaker or crossover design, I wonder if someone could help me out with

this

simple question.

in a typical 2 way speaker, the bass driver dissipates many times as

much

power as the tweeter. however, the nominal impedance of the two drivers

is

often similar. if the voltage across the two is the same and the

impedance

is the same, how does the bass driver draw so much more power than the
tweeter?

I realise this is a gross simplification of the actual design of a

speaker.

Is it the crossover that increases the impedance as seen by the

amplifier?

or am I totally missing something

Andy



The tweeter crossover network contains an attenuator.

A



OK, thanks. This is obviously more difficult than I originally thought.

Here's my actual problem: I have a pair of bi-wireable speakers and I would
like to attenuate the top end by 2-3db. Is it possible to do this without
taking them apart - i.e. by connecting a series resistor and/or l-pad onto
the tweeter's speaker terminals?


Absolutely no problem if the unit is bi-wireable, you can add an L-pad
to the HF terminals.

This may slightly affect the resposne of the HF crossover section as it
will increase the source impeadance seen on the input.

Most terminals are on a plastic panel that can be removed. If your is,
you could solder the extra resistors on the inside after you are happy
with the sound.

A