My deck (Eclipse 8053) has biamp outputs - provided the "rear" channels are
switched to become "mid" and the front channels become the "high" outputs.

So, in biamp mode I have no rear channels---but the deck also has a "Fixed
Out" that runs at full volume only.

I ran this fixed out to an old alpine 10-band that I am using to control the
rear speakers. Fuzztone. On the EQ, there is an led array that shows total
overload unless I lower all the bands to minus 12 db (or -15 db, maybe--I
forget) and it's still slightly distorted at those settings.

My plan is to try a 10k resistor (guessing on the value here) inline with
the tip of the interconnect rca before the EQ.

Is this plan valid???

Another idea, better, would be to able to sum the mids & highs for the back
speakers *without having them be summed to the front speakers. That way,
fronts and rear would be controlled by the head unit's volume control. I
don't know how to build this circuit, other than buying a little mixer.

My plan is to try a 10k resistor (guessing on the value here) inline with
the tip of the interconnect rca before the EQ.

Check your amp's manual. A lot of times there's a value for input
impedance. It's generally in the 10-30k range. Then just treat it as a
voltage divider.

PS Are you saying that this output isn't controlled by the volume knob?


Is this plan valid???

Another idea, better, would be to able to sum the mids & highs for the
back
speakers *without having them be summed to the front speakers. That way,
fronts and rear would be controlled by the head unit's volume control. I
don't know how to build this circuit, other than buying a little mixer.

It's a pain. Leave it alone.

Why not run just the low output to the rears? Where's the cutoff?

Yes the "fixed" output I am trying to tone down is not controlled by
any voulme control on the head unit, other than the mute control.

I need a full range signal and not just mid-bass at the request of my
daughter passengers in the back. The xover is set for 1.6k hz, nice
and low

The spec in the manual says 55 ohm output impedance. (not 55k)

So does that mean if I build an interconnect with a 55 ohm resistor in
the tip, the signal will be reduced 3 db??




On Wed, 18 Feb 2004 08:11:31 -0500, "MZ"
wrote:

My plan is to try a 10k resistor (guessing on the value here) inline with
the tip of the interconnect rca before the EQ.

Check your amp's manual. A lot of times there's a value for input
impedance. It's generally in the 10-30k range. Then just treat it as a
voltage divider.

PS Are you saying that this output isn't controlled by the volume knob?


Is this plan valid???

Another idea, better, would be to able to sum the mids & highs for the
back
speakers *without having them be summed to the front speakers. That way,
fronts and rear would be controlled by the head unit's volume control. I
don't know how to build this circuit, other than buying a little mixer.

It's a pain. Leave it alone.

Why not run just the low output to the rears? Where's the cutoff?

The spec in the manual says 55 ohm output impedance. (not 55k)

So does that mean if I build an interconnect with a 55 ohm resistor in
the tip, the signal will be reduced 3 db??

No, that's the output impedance of the head unit. What you need is the
input impedance of the amplifier. Oh yeah, and you may want to reduce by
more than 3dB.

The spec in the manual says 55 ohm output impedance. (not 55k)

So does that mean if I build an interconnect with a 55 ohm resistor in
the tip, the signal will be reduced 3 db??

No, that's the output impedance of the head unit. What you need is the
input impedance of the amplifier. Oh yeah, and you may want to reduce by
more than 3dB.

Oh yeah, the other way to do it is to use 2 resistors and create a voltage
divider.

Really, you don't need to know the input impedance. All it does for you is
give you a good starting point. If you can't find it out, just assume 20k
ohms.

PS-

If you use a potentiometer (say, 200k ohms or more range), you can dial in
the ideal value of resistance, then use a resistor of that value as the
permanent solution.

--
Mark
remove "remove" and "spam" to reply
"MZ" wrote in message
...
The spec in the manual says 55 ohm output impedance. (not 55k)

So does that mean if I build an interconnect with a 55 ohm resistor in
the tip, the signal will be reduced 3 db??

No, that's the output impedance of the head unit. What you need is the
input impedance of the amplifier. Oh yeah, and you may want to reduce
by
more than 3dB.

Oh yeah, the other way to do it is to use 2 resistors and create a voltage
divider.

Really, you don't need to know the input impedance. All it does for you
is
give you a good starting point. If you can't find it out, just assume 20k
ohms.