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#81
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"Randy Yates" wrote in message ... Descriptionism in scientific and technical fields leads to chaos. Yes, or maybe it just sorts the technically competent from the technically illiterate. As is the case here. And maybe you need to stop having sex with your mother while she's in between customers. Well THAT reply sure sorted out YOUR level of intelligence anyway. MrT. |
#82
Posted to rec.audio.pro,rec.audio.tech
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"Mr.T" MrT@home wrote:
"Randy Yates" wrote in message ... Descriptionism in scientific and technical fields leads to chaos. Yes, or maybe it just sorts the technically competent from the technically illiterate. As is the case here. And maybe you need to stop having sex with your mother while she's in between customers. Well THAT reply sure sorted out YOUR level of intelligence anyway. Maybe he's just talking from his own familial experience. (This whole non****ing thread has gotten way beyond rediculous. Y'all get yer ****in' meters and measure what you need to measure. Then go fishing.) -- ha Iraq is Arabic for Vietnam |
#83
Posted to rec.audio.pro,rec.audio.tech
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On Oct 24, 5:06 pm, Mike Rivers wrote:
On Oct 24, 5:04 pm, Mark wrote: maybe real world cases in audio land.... but not true of real world cases in RF land where most things are power into /out of 50 Ohms Please note that you're posting to rec.AUIDO.pro and rec.AUDIO.tech. If you want to talk about RF, please post to rec.RF.bs 100 Watts RMS is also unfortunatley common but is always a mistake because it is mathematically incorrect. All right, what's wrong now? It is correct to say RMS voltage. It is correct to say RMS current. It is correct to say AVERAGE power. It is not correct to say RMS power. RMS Voltage squared/resistance = AVERAGE power. RMS Voltage x RMS current = AVERAGE power. RMS current squared x reistance = AVERAGE power. Mark |
#84
Posted to rec.audio.pro,rec.audio.tech
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"Randy Yates" wrote in message
... Maybe? How many authoritative sources do you need to see it defined in before you concur that it IS a power ratio? Again, you're begging the question of what the meaning of "is" is. How about if we start tugging on the definition of watt (1 joule/second). "Well, *maybe* it refers to 1 joule / second, but Webermatic had a manufacturing problem 10 years ago in their power meter product in which it registered 1.1 joules/second, so now we don't really know what it means." Or, "John C. PowerEngineer used it for energy in his report to the DOE 4 years ago and it has now become common practice that it refers to ENERGY." Descriptionism in scientific and technical fields leads to chaos. Not if the vast majority of practitioners agree about what they're measuring. Communication is about terms that are mutually agreed-upon, and the vast majority of people working in audio agree about dBu as a way to express a voltage measurement. So communication takes place. Peace, Paul |
#85
Posted to rec.audio.pro,rec.audio.tech
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"Randy Yates" wrote in message
... "Mr.T" MrT@home writes: "Randy Yates" wrote in message ... Descriptionism in scientific and technical fields leads to chaos. Yes, or maybe it just sorts the technically competent from the technically illiterate. As is the case here. And maybe you need to stop having sex with your mother while she's in between customers. Plonk. Peace, Paul |
#86
Posted to rec.audio.pro,rec.audio.tech
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On Wed, 24 Oct 2007 19:29:50 -0700, Mark wrote:
On Oct 24, 5:06 pm, Mike Rivers wrote: On Oct 24, 5:04 pm, Mark wrote: maybe real world cases in audio land.... but not true of real world cases in RF land where most things are power into /out of 50 Ohms Please note that you're posting to rec.AUIDO.pro and rec.AUDIO.tech. If you want to talk about RF, please post to rec.RF.bs 100 Watts RMS is also unfortunatley common but is always a mistake because it is mathematically incorrect. All right, what's wrong now? It is correct to say RMS voltage. It is correct to say RMS current. It is correct to say AVERAGE power. It is not correct to say RMS power. RMS Voltage squared/resistance = AVERAGE power. RMS Voltage x RMS current = AVERAGE power. RMS current squared x reistance = AVERAGE power. Mark Absolutely spot on. Full marks to that man! d -- Pearce Consulting http://www.pearce.uk.com |
#87
Posted to rec.audio.pro,rec.audio.tech
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"Mr.T" wrote: "Eeyore" wrote in message NO. Energy and power are perfectly well defined. Wasn't that his point! No need to accept new definitions caused by incorrect usage. There's nothing incorrect about using dBs for voltage. Indeed since audio no longer uses matched impedance working (and hasn't fro many decades), using dBm is not only pointless and irrelevant but wholly WRONG. Graham |
#88
Posted to rec.audio.pro,rec.audio.tech
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Randy Yates wrote: "Mr.T" MrT@home writes: "Randy Yates" wrote in message Descriptionism in scientific and technical fields leads to chaos. Yes, or maybe it just sorts the technically competent from the technically illiterate. As is the case here. And maybe you need to stop having sex with your mother while she's in between customers CRETIN. |
#89
Posted to rec.audio.pro,rec.audio.tech
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Randy Yates wrote: Eeyore writes: [...] Energy and power are perfectly well defined. Precisely. And so are decibels. As either voltage or current or power or indeed any other unit you care to mention. Graham |
#90
Posted to rec.audio.pro,rec.audio.tech
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On Oct 24, 10:29 pm, Mark wrote:
It is correct to say RMS voltage. It is correct to say RMS current. It is correct to say AVERAGE power. It is not correct to say RMS power. Ah, yes, you're preaching to the wrong group again. This is another case where common use within a specific genre has expanded, or rather, overtaken the original definition. In audio, we usually only use RMS on spec sheets, and in this business, spec sheets are products of the Marketing department, not the Engineering department. There's a way to calculate RMS voltage or current using the definition, but for anything other than a simple and periodic waveform, it's pretty difficult to calculate. So we use "RMS" to mean "the average voltage, current, OR POWER measured or calculated for a sine wave." Most people who know enough to be dangerous will tell you that RMS is 0.707 x peak, and this is true for the special case of a sine wave. This falls down when the waveform is music, speech, or anything complex. But since people who write spec sheets usually use sine wave measurements, for this special case (which is understood by the virtual "everybody") it's valid. There aren't too many people who connect the output of an amplifier to a resistor, put the resistor in a bucket of water, play some music into it, and see how much the water heats up. That'll tell you the RMS power. |
#91
Posted to rec.audio.pro,rec.audio.tech
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On Thu, 25 Oct 2007 03:48:52 -0700, Mike Rivers
wrote: On Oct 24, 10:29 pm, Mark wrote: It is correct to say RMS voltage. It is correct to say RMS current. It is correct to say AVERAGE power. It is not correct to say RMS power. Ah, yes, you're preaching to the wrong group again. This is another case where common use within a specific genre has expanded, or rather, overtaken the original definition. In audio, we usually only use RMS on spec sheets, and in this business, spec sheets are products of the Marketing department, not the Engineering department. There's a way to calculate RMS voltage or current using the definition, but for anything other than a simple and periodic waveform, it's pretty difficult to calculate. So we use "RMS" to mean "the average voltage, current, OR POWER measured or calculated for a sine wave." Most people who know enough to be dangerous will tell you that RMS is 0.707 x peak, and this is true for the special case of a sine wave. This falls down when the waveform is music, speech, or anything complex. But since people who write spec sheets usually use sine wave measurements, for this special case (which is understood by the virtual "everybody") it's valid. There aren't too many people who connect the output of an amplifier to a resistor, put the resistor in a bucket of water, play some music into it, and see how much the water heats up. That'll tell you the RMS power. No it won't. It will tell you the average power. Mathematically it is possible to take the RMS of power, but I have no idea what you might do with the figure you end up with, because it has no possible meaning that I'm aware of. d -- Pearce Consulting http://www.pearce.uk.com |
#92
Posted to rec.audio.pro,rec.audio.tech
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On Oct 25, 6:53 am, (Don Pearce) wrote:
Mathematically it is possible to take the RMS of power, but I have no idea what you might do with the figure you end up with, because it has no possible meaning that I'm aware of. Did you read what I wrote about marketing? THAT'S the real world that we're in here. "RMS Power" looks good to those reading the spec sheet. If it said "Average power" the reader would think the company is trying to pull a fast one. Actually, they mostly just say "Power" or "Maximum power" which is even less meaningful. At least if you measure RMS voltage of a sine wave going into a resistor, you can compute a number that agrees with what you see on the spec sheet. Most people would call that "RMS Power" if they called it anything other than "power." Remember IHF Music Power? |
#93
Posted to rec.audio.pro,rec.audio.tech
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On Thu, 25 Oct 2007 04:14:12 -0700, Mike Rivers
wrote: On Oct 25, 6:53 am, (Don Pearce) wrote: Mathematically it is possible to take the RMS of power, but I have no idea what you might do with the figure you end up with, because it has no possible meaning that I'm aware of. Did you read what I wrote about marketing? THAT'S the real world that we're in here. "RMS Power" looks good to those reading the spec sheet. If it said "Average power" the reader would think the company is trying to pull a fast one. Actually, they mostly just say "Power" or "Maximum power" which is even less meaningful. At least if you measure RMS voltage of a sine wave going into a resistor, you can compute a number that agrees with what you see on the spec sheet. Most people would call that "RMS Power" if they called it anything other than "power." But they would be wrong. We are supposed to be experts on this group, so we have no excuse for misusing the technical terms. Remember IHF Music Power? Oh yes. Unfortunately d -- Pearce Consulting http://www.pearce.uk.com |
#94
Posted to rec.audio.pro,rec.audio.tech
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"Paul Stamler" writes:
"Randy Yates" wrote in message ... Maybe? How many authoritative sources do you need to see it defined in before you concur that it IS a power ratio? Again, you're begging the question of what the meaning of "is" is. So are you. How about if we start tugging on the definition of watt (1 joule/second). "Well, *maybe* it refers to 1 joule / second, but Webermatic had a manufacturing problem 10 years ago in their power meter product in which it registered 1.1 joules/second, so now we don't really know what it means." Or, "John C. PowerEngineer used it for energy in his report to the DOE 4 years ago and it has now become common practice that it refers to ENERGY." Descriptionism in scientific and technical fields leads to chaos. Not if the vast majority of practitioners agree about what they're measuring. In the case of the bel, they don't. And in that situation, I'll take the definition that has long been established in black-and-white over current individual preference. I'll accede that my assertion was perhaps too broad ( "intellectual property"). But in the case of fundamental physical quantities, I think it is accurate. Can you cite a counter-example? Communication is about terms that are mutually agreed-upon, and the vast majority of people working in audio agree about dBu as a way to express a voltage measurement. So communication takes place. I never said it wasn't a way to express voltage. I just said it is indirectly voltage, and directly power. One other aspect of my perspective that hasn't yet been mentioned: The fruitfulness of it. If you always go back to the definition of a bel as the log of a ratio of powers, then you avoid the confusion that seems to regularly pop up on the subject. -- % Randy Yates % "Remember the good old 1980's, when %% Fuquay-Varina, NC % things were so uncomplicated?" %%% 919-577-9882 % 'Ticket To The Moon' %%%% % *Time*, Electric Light Orchestra http://www.digitalsignallabs.com |
#96
Posted to rec.audio.pro,rec.audio.tech
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On Thu, 25 Oct 2007 07:31:52 -0400, Randy Yates
wrote: (Don Pearce) writes: On Thu, 25 Oct 2007 04:14:12 -0700, Mike Rivers wrote: On Oct 25, 6:53 am, (Don Pearce) wrote: Mathematically it is possible to take the RMS of power, but I have no idea what you might do with the figure you end up with, because it has no possible meaning that I'm aware of. Did you read what I wrote about marketing? THAT'S the real world that we're in here. "RMS Power" looks good to those reading the spec sheet. If it said "Average power" the reader would think the company is trying to pull a fast one. Actually, they mostly just say "Power" or "Maximum power" which is even less meaningful. At least if you measure RMS voltage of a sine wave going into a resistor, you can compute a number that agrees with what you see on the spec sheet. Most people would call that "RMS Power" if they called it anything other than "power." But they would be wrong. We are supposed to be experts on this group, so we have no excuse for misusing the technical terms. If one takes the "RMS" in "RMS Power" as applying to the voltage that is used to calculate that power, then it makes some sense. That makes no sense at all. What makes sense is to say the average power, as that is precisely what you are measuring. Anyway, while 90% of people understand vaguely what the word average means; I bet not 0.01% could tell you what RMS means. But I'm not really arguing we keep the term. Having been a rock musician in the 70's (can you say MiniMoog?), it is nostalgic for me. I can do better than that - I can say Mellotron! d -- Pearce Consulting http://www.pearce.uk.com |
#97
Posted to rec.audio.pro,rec.audio.tech
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On Oct 25, 7:24 am, Randy Yates wrote:
Not if the vast majority of practitioners agree about what they're measuring. In the case of the bel, they don't. And in that situation, I'll take the definition that has long been established in black-and-white over current individual preference. What "vast majority" are you talking about? I'll bet there are more guitar players than there are RF engineers. In what units would you state the output level of a microphone preamp, and to whom? I know you don't want to accept that anything with dB in it can be "units," but that's what dBu is. I completely agree that stating "Maximum output: 22 dB" is completely wrong, but "Maximum output: +22 dBu" is completely understood and, in my world, correct. I never said it wasn't a way to express voltage. I just said it is indirectly voltage, and directly power. But nobody cares about power when speaking about interfacing devices that produce and sink negligible power. It's the voltage that's important. If there's an ambiguous usage, it's in saying "Gain: 60 dB" rather than "Voltage gain: 60 dB." But in the world of voltage interfacing of audio equipment, "voltage" is understood. When using impedance-matched connections, it's understood that the open circuit voltage will drop in half when (properly) loaded. But within relatively small confines, the load impedance is high enough so that voltage drop will be insignificant. One other aspect of my perspective that hasn't yet been mentioned: The fruitfulness of it. If you always go back to the definition of a bel as the log of a ratio of powers, then you avoid the confusion that seems to regularly pop up on the subject. I'd hardly think the confusion regularly pops up. It only pops up when someone tries to talk about devices that involve power, and usually outside the context of audio interface. Unless you think that everyone who talks about audio interfacing is hopelessly confused and none of the numbers they've been using for years are valid. You'd have a hard time with that argument. It's like someone from Great Britain goes into a bar where there's a Redskins game on TV and asks for them to change the channel to one with a football game. That's essentially what you're doing here. Go back to your own bar and leave us alone in our well understood befuddlement . |
#98
Posted to rec.audio.pro,rec.audio.tech
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(Don Pearce) writes:
On Thu, 25 Oct 2007 07:31:52 -0400, Randy Yates wrote: (Don Pearce) writes: On Thu, 25 Oct 2007 04:14:12 -0700, Mike Rivers wrote: On Oct 25, 6:53 am, (Don Pearce) wrote: Mathematically it is possible to take the RMS of power, but I have no idea what you might do with the figure you end up with, because it has no possible meaning that I'm aware of. Did you read what I wrote about marketing? THAT'S the real world that we're in here. "RMS Power" looks good to those reading the spec sheet. If it said "Average power" the reader would think the company is trying to pull a fast one. Actually, they mostly just say "Power" or "Maximum power" which is even less meaningful. At least if you measure RMS voltage of a sine wave going into a resistor, you can compute a number that agrees with what you see on the spec sheet. Most people would call that "RMS Power" if they called it anything other than "power." But they would be wrong. We are supposed to be experts on this group, so we have no excuse for misusing the technical terms. If one takes the "RMS" in "RMS Power" as applying to the voltage that is used to calculate that power, then it makes some sense. That makes no sense at all. What makes sense is to say the average power, as that is precisely what you are measuring. Anyway, while 90% of people understand vaguely what the word average means; I bet not 0.01% could tell you what RMS means. 0.01% of the people here on this group? You must have some trick up your sleeve. RMS = root-mean-square, the square root of the mean of the square. In general, given a function f(t), the RMS value F of f(t) is F = limit as T approaches infinity ((1/T) * integral from -T/2 to +T/2 f^2(t) dt)^(1/2)) But I'm not really arguing we keep the term. Having been a rock musician in the 70's (can you say MiniMoog?), it is nostalgic for me. I can do better than that - I can say Mellotron! As in, you owned one? That's cool. I think I had a 10-second opportunity to pound on one in a music store once - it was very eery. -- % Randy Yates % "The dreamer, the unwoken fool - %% Fuquay-Varina, NC % in dreams, no pain will kiss the brow..." %%% 919-577-9882 % %%%% % 'Eldorado Overture', *Eldorado*, ELO http://www.digitalsignallabs.com |
#99
Posted to rec.audio.pro,rec.audio.tech
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On Thu, 25 Oct 2007 07:49:09 -0400, Randy Yates
wrote: (Don Pearce) writes: On Thu, 25 Oct 2007 07:31:52 -0400, Randy Yates wrote: (Don Pearce) writes: On Thu, 25 Oct 2007 04:14:12 -0700, Mike Rivers wrote: On Oct 25, 6:53 am, (Don Pearce) wrote: Mathematically it is possible to take the RMS of power, but I have no idea what you might do with the figure you end up with, because it has no possible meaning that I'm aware of. Did you read what I wrote about marketing? THAT'S the real world that we're in here. "RMS Power" looks good to those reading the spec sheet. If it said "Average power" the reader would think the company is trying to pull a fast one. Actually, they mostly just say "Power" or "Maximum power" which is even less meaningful. At least if you measure RMS voltage of a sine wave going into a resistor, you can compute a number that agrees with what you see on the spec sheet. Most people would call that "RMS Power" if they called it anything other than "power." But they would be wrong. We are supposed to be experts on this group, so we have no excuse for misusing the technical terms. If one takes the "RMS" in "RMS Power" as applying to the voltage that is used to calculate that power, then it makes some sense. That makes no sense at all. What makes sense is to say the average power, as that is precisely what you are measuring. Anyway, while 90% of people understand vaguely what the word average means; I bet not 0.01% could tell you what RMS means. 0.01% of the people here on this group? You must have some trick up your sleeve. No, people generally. I'm thinking about what you read on glossy brochures in shops. RMS = root-mean-square, the square root of the mean of the square. In general, given a function f(t), the RMS value F of f(t) is F = limit as T approaches infinity ((1/T) * integral from -T/2 to +T/2 f^2(t) dt)^(1/2)) But I'm not really arguing we keep the term. Having been a rock musician in the 70's (can you say MiniMoog?), it is nostalgic for me. I can do better than that - I can say Mellotron! As in, you owned one? That's cool. I think I had a 10-second opportunity to pound on one in a music store once - it was very eery. Yup. I think it was about tenth hand and the tapes had snapped and been re-attached so many times that most of the keys only managed a couple of seconds. d -- Pearce Consulting http://www.pearce.uk.com |
#100
Posted to rec.audio.pro,rec.audio.tech
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Randy Yates wrote:
If one takes the "RMS" in "RMS Power" as applying to the voltage that is used to calculate that power, then it makes some sense. Not much. The *only* thing that makes technical sense and is truly compatible with the intention behind "RMS power" is to say "sine wave power". If only that was the standard way of describing am amplifier rating, we'd all be talking about the same thing and we wouldn't have to waste time arguing about the misapplication of the term "RMS". If you refined that to PURE sine wave Marketing might even be happy about the implied pristine quality too. It's often forgotten in these discussions that the power an amplifier can deliver at clipping point varies with waveform. An amplifier with 100W max sine wave output could deliver 200W square wave, and that would be real honest power, whether measured by heating effect or calculated from the RMS voltage. As mentioned before, that 0.707 ratio holds only for sine waves. Anahata |
#101
Posted to rec.audio.pro,rec.audio.tech
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Mike Rivers writes:
[...] On Oct 25, 7:24 am, Randy Yates wrote: I never said it wasn't a way to express voltage. I just said it is indirectly voltage, and directly power. But nobody cares about power when speaking about interfacing devices that produce and sink negligible power. It's the voltage that's important. This is a damned-confusing situation semantically. I agree that dBu is used to specify voltage. But dBu is the log of a ratio of powers. FURTHER, dBu has NO units. 20*log(V1/VR), when V1 and VR are both in volts, is unitless. We could also say, assuming for example a resistance of 1 ohm, that the voltage at a point in a circuit is 10 milliwatts, meaning that it is the voltage that would produce 10 milliwatts into a 1 ohm resistance. No, we're not interested in watts but we're deriving the quantity we are interested in, volts, through it. Such is the situation with dBu (and similarly with other dB "units"). And don't give me the "watts are not volts" argument. Volts are not [] (nothing, unitless), either! Our minds are wonderful things - they can take this complex situation and arrive at the "important information" almost instantly. But if we forget this fact (that it is most directly a ratio of powers), we may also forget how to manipulate the quantities involved properly. -- % Randy Yates % "Midnight, on the water... %% Fuquay-Varina, NC % I saw... the ocean's daughter." %%% 919-577-9882 % 'Can't Get It Out Of My Head' %%%% % *El Dorado*, Electric Light Orchestra http://www.digitalsignallabs.com |
#102
Posted to rec.audio.pro,rec.audio.tech
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#103
Posted to rec.audio.pro,rec.audio.tech
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On Thu, 25 Oct 2007 08:21:57 -0400, Randy Yates
wrote: Mike Rivers writes: [...] On Oct 25, 7:24 am, Randy Yates wrote: I never said it wasn't a way to express voltage. I just said it is indirectly voltage, and directly power. But nobody cares about power when speaking about interfacing devices that produce and sink negligible power. It's the voltage that's important. This is a damned-confusing situation semantically. I agree that dBu is used to specify voltage. But dBu is the log of a ratio of powers. No, the dBu is the log of the ratio of what used to be powers, but is now voltage. FURTHER, dBu has NO units. 20*log(V1/VR), when V1 and VR are both in volts, is unitless. dBu IS the unit (inclusive of its dimension) We could also say, assuming for example a resistance of 1 ohm, that the voltage at a point in a circuit is 10 milliwatts, meaning that it is the voltage that would produce 10 milliwatts into a 1 ohm resistance. No, we're not interested in watts but we're deriving the quantity we are interested in, volts, through it. Derived units are always tricky. Such is the situation with dBu (and similarly with other dB "units"). And don't give me the "watts are not volts" argument. Volts are not [] (nothing, unitless), either! Our minds are wonderful things - they can take this complex situation and arrive at the "important information" almost instantly. But if we forget this fact (that it is most directly a ratio of powers), we may also forget how to manipulate the quantities involved properly. For most of the audio chain it is the voltage, not the power that matters (to us, semantically, that is - to the electronics the power always matters). Where that assumption fails is at the ends of the chain - the microphone and the speakers. For the speakers the need for a power rating is obvious, but it may be less so for a microphone. But in defining the signal to noise ratio you get off a microphone, what you need is the ratio of signal power to noise power, and you have to juggle impedances to optimize that ratio. Unfortunately the specs tend to be written in voltage terms, so if you want to do any meaningful calculations, you have to translate. d -- Pearce Consulting http://www.pearce.uk.com |
#104
Posted to rec.audio.pro,rec.audio.tech
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On Thu, 25 Oct 2007 13:29:53 +0100, Laurence Payne
NOSPAMlpayne1ATdsl.pipex.com wrote: On Thu, 25 Oct 2007 11:55:57 GMT, (Don Pearce) wrote: That makes no sense at all. What makes sense is to say the average power, as that is precisely what you are measuring. Anyway, while 90% of people understand vaguely what the word average means; I bet not 0.01% could tell you what RMS means. 0.01% of the people here on this group? You must have some trick up your sleeve. No, people generally. I'm thinking about what you read on glossy brochures in shops. Even punters often have a vague idea that RMS is real, other figures are marketing-speak, even if they don't know the technicalities. Well, they obviously don't know it is real, because it isn't. But they may feel that it is a "trustworthy" number. They still couldn't tell you what it actually means though. d -- Pearce Consulting http://www.pearce.uk.com |
#105
Posted to rec.audio.pro,rec.audio.tech
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Mike Rivers wrote: On Oct 25, 6:53 am, (Don Pearce) wrote: Mathematically it is possible to take the RMS of power, but I have no idea what you might do with the figure you end up with, because it has no possible meaning that I'm aware of. Did you read what I wrote about marketing? THAT'S the real world that we're in here. "RMS Power" looks good to those reading the spec sheet. If it said "Average power" the reader would think the company is trying to pull a fast one. Actually, they mostly just say "Power" or "Maximum power" which is even less meaningful. At least if you measure RMS voltage of a sine wave going into a resistor, you can compute a number that agrees with what you see on the spec sheet. Most people would call that "RMS Power" if they called it anything other than "power." Remember IHF Music Power? I think you've missed what Don was trying to explain. RMS has a precise mathematical definition (root mean square) as does average. When you multiply RMS volts by RMS amps you get AVERAGE watts. RMS watts would be something else and largely meaningless. It confused me for some years too. Graham |
#106
Posted to rec.audio.pro,rec.audio.tech
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Randy Yates wrote: FURTHER, dBu has NO units. 20*log(V1/VR), when V1 and VR are both in volts, is unitless. That's not how you calculate dBu. dBu = 20log10(signal_voltage/0.775V). Graham |
#107
Posted to rec.audio.pro,rec.audio.tech
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On Oct 25, 8:33 am, (Don Pearce) wrote:
Even punters often have a vague idea that RMS is real, other figures are marketing-speak, even if they don't know the technicalities. Well, they obviously don't know it is real, because it isn't. But they may feel that it is a "trustworthy" number. They still couldn't tell you what it actually means though. That's moving toward a good point about being "trustworthy." They tend to use that number as a means of comparison between similar products. But if it's truly meaningless, the one with the bigger number could deliver less usable power than the one with the smaller number. This has been true more than we'd like to know about. The good news is that most reputable manufacturers make the measurement in the same way - continuous sine wave, probably around 1 kHz or so - so the data is comparable. But a power amplifier with a skimpy power supply might have an impressive "RMS Power" number be inadequate for driving a subwoofer because power supply poops out in less than a single cycle at lower frequencies. |
#108
Posted to rec.audio.pro,rec.audio.tech
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SPL definition
On Oct 25, 8:21 am, Randy Yates wrote:
I agree that dBu is used to specify voltage. But dBu is the log of a ratio of powers. No, dBu is 20 times the log of the ratio of the measured voltage and 0.775 volts. Since you don't know the current or impedance, you have no idea what the power is. You aren't one of those people who confused dB, dBu, and dBm are you? That's another can of worms since in audio, dBm is nearly always measured with a 600 ohm source and load and in RF, it's most commonly 50 ohms. Watts is always watts, but when you want to know how many volts you have across that 600 or 50 ohm load, it's different. And in low level audio interfacing, we like to talk about volts. FURTHER, dBu has NO units. This is true in itself, but if you know the number of dBu, you can, if you actually want to, easily and unambiguously calculate the number of volts. And since we're often interested in voltage gain, knowing the input and output as a ratio to a standard reference, calculating voltage is simple subtraction. It's just a convenient way of working if everyone plays by the same rules. We could also say, assuming for example a resistance of 1 ohm, that the voltage at a point in a circuit is 10 milliwatts, meaning that it is the voltage that would produce 10 milliwatts into a 1 ohm resistance. Why in the world would we say that? Volts is volts, watts is watts. What we DID say is that we'll call 0 dBu the voltage measured across a 600 ohm resistor when 1 milliwatt is delivered to that resistor. But that doesn't mean you can connect a 600 ohm load across a device that's putting out 0.775 open circuit and expect to measure 1.29 milliamps (or 1 milliwatt). Our minds are wonderful things - they can take this complex situation and arrive at the "important information" almost instantly. But if we forget this fact (that it is most directly a ratio of powers), we may also forget how to manipulate the quantities involved properly. They can also take a simple and easily understood concept and make it hopelessly meaningless just by insisting that a definition is incorrectly used. |
#109
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SPL definition
Mike Rivers wrote: Randy Yates wrote: FURTHER, dBu has NO units. This is true in itself Actually it's not. The units of dBu are Volts. In units of magnitude of 0.775. Graham |
#110
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SPL definition
Eeyore writes:
Mike Rivers wrote: Randy Yates wrote: FURTHER, dBu has NO units. This is true in itself Actually it's not. The units of dBu are Volts. In units of magnitude of 0.775. Wow. Utterly amazing. I actually thought you knew better, too, Eeyore. The amount of insanity and chaos on this topic is scary. -- % Randy Yates % "She's sweet on Wagner-I think she'd die for Beethoven. %% Fuquay-Varina, NC % She love the way Puccini lays down a tune, and %%% 919-577-9882 % Verdi's always creepin' from her room." %%%% % "Rockaria", *A New World Record*, ELO http://www.digitalsignallabs.com |
#111
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SPL definition
Randy Yates wrote: Eeyore writes: Mike Rivers wrote: Randy Yates wrote: FURTHER, dBu has NO units. This is true in itself Actually it's not. The units of dBu are Volts. In units of magnitude of 0.775. Wow. Utterly amazing. I actually thought you knew better, too, Eeyore. The amount of insanity and chaos on this topic is scary. You're seriously out of touch with reality. dBu are no different from dBV aside from an small offset of ~ 2.2dB. X dBu = X-2.2 dBV. How do you explain dBV and dB SPL in your power-centric world ? Graham |
#112
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SPL definition
On Oct 25, 11:22 am, Eeyore
wrote: The units of dBu are Volts. In units of magnitude of 0.775. I was gong to say that, but I figured Mr. Semantic would give me an argument. Let him argue with you for a change. When you look at it as arithmetic, it actually has no units: Volts divided by volts is unitless (as opposed to volts plus volts). What we can (and do) say, however, is that 0 dBu (a specific number) equals 0.775 volts. That's not precisely the same as dBu equals volts. |
#113
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SPL definition
Don Pearce wrote
... Mathematically it is possible to take the RMS of power, but I have no idea what you might do with the figure you end up with, because it has no possible meaning that I'm aware of. You may wish to describe its statistical distribution in time, or with respect to some other variable. Its standard deviation or variance, for example. Unlike the average, the rms of power would not be zero for a capacitance or inductance. How that might be useful I don't know. Ian |
#114
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SPL definition
Mike Rivers writes:
On Oct 25, 11:22 am, Eeyore wrote: The units of dBu are Volts. In units of magnitude of 0.775. I was gong to say that, but I figured Mr. Semantic would give me an argument. Let him argue with you for a change. When you look at it as arithmetic, it actually has no units: Volts divided by volts is unitless (as opposed to volts plus volts). What we can (and do) say, however, is that 0 dBu (a specific number) equals 0.775 volts. That's not precisely the same as dBu equals volts. This discussion has been very revealing. -- % Randy Yates % "And all that I can do %% Fuquay-Varina, NC % is say I'm sorry, %%% 919-577-9882 % that's the way it goes..." %%%% % Getting To The Point', *Balance of Power*, ELO http://www.digitalsignallabs.com |
#115
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SPL definition
Randy Yates wrote:
Mike Rivers writes: On Oct 25, 11:22 am, Eeyore wrote: The units of dBu are Volts. In units of magnitude of 0.775. I was gong to say that, but I figured Mr. Semantic would give me an argument. Let him argue with you for a change. When you look at it as arithmetic, it actually has no units: Volts divided by volts is unitless (as opposed to volts plus volts). What we can (and do) say, however, is that 0 dBu (a specific number) equals 0.775 volts. That's not precisely the same as dBu equals volts. This discussion has been very revealing. Why don't you guys just measure your dicks and be done with it :-) |
#116
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SPL definition
Romeo Rondeau writes:
Why don't you guys just measure your dicks and be done with it :-) Should we use the dBD scale? (Gives new meaning to dBV...) -- % Randy Yates % "With time with what you've learned, %% Fuquay-Varina, NC % they'll kiss the ground you walk %%% 919-577-9882 % upon." %%%% % '21st Century Man', *Time*, ELO http://www.digitalsignallabs.com |
#117
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SPL definition
Les Cargill writes:
They're baaaaaaack. http://www.mellotron.com Who'd want one now when you can have a sampler with 24 bits / 120 dB SNR? -- % Randy Yates % "Watching all the days go by... %% Fuquay-Varina, NC % Who are you and who am I?" %%% 919-577-9882 % 'Mission (A World Record)', %%%% % *A New World Record*, ELO http://www.digitalsignallabs.com |
#118
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SPL definition
On Oct 25, 12:51 pm, Randy Yates wrote:
Romeo Rondeau writes: Why don't you guys just measure your dicks and be done with it :-) Should we use the dBD scale? (Gives new meaning to dBV...) dB(D) is a real scale, D weighting for noise measurements near aircraft, airports etc. bobs Bob Smith BS Studios we organize chaos http://www.bsstudios.com |
#119
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SPL definition
"Randy Yates" wrote in message
... "Keith Carlson" writes: Well, I know what the definition is, but I'm trying to understand where it comes from to help me remember it. I tend to get SPL vs sound power level mixed up (as well as when it's 3db or 6db that represents a doubling). The definition I know is: SPL = 20 log (p1/p0), or 10 log (p1/p0)^2 (where "^2" means to the power of 2) I understand that the factor of 10 is because it's expressed in decibels as opposed to bels. My specific question, though, is why is the ratio squared? If p0 is the reference pressure level, and p1 is the measured pressure level, why isn't SPL just the log of that ratio, similar to the way sound power level is the log of power level ratio? The primary reason is simply that anything involving decibels is by definition a ratio of powers, and acoustic power is related to the square of the pressure level. -- % Randy Yates % "My Shangri-la has gone away, fading like %% Fuquay-Varina, NC % the Beatles on 'Hey Jude'" %%% 919-577-9882 % %%%% % 'Shangri-La', *A New World Record*, ELO http://www.digitalsignallabs.com Thanks, Randy, and everyone else who answered. I didn't know this one of "those" questions that stirs up an old debate. It helps me to know that a decibel or bel is defined as the log of a ratio of power levels. Gives me something to remember then, that if it's acoustic pressure, or voltage, or anything where its square is related to power, that it's going to be 20x rather than 10x (for decibel). And from there I can remember figure whether it's 3dB or 6 dB that represents (roughly) a doubling of the ratio. |
#120
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SPL definition
"Keith Carlson" writes:
"Randy Yates" wrote in message ... "Keith Carlson" writes: Well, I know what the definition is, but I'm trying to understand where it comes from to help me remember it. I tend to get SPL vs sound power level mixed up (as well as when it's 3db or 6db that represents a doubling). The definition I know is: SPL = 20 log (p1/p0), or 10 log (p1/p0)^2 (where "^2" means to the power of 2) I understand that the factor of 10 is because it's expressed in decibels as opposed to bels. My specific question, though, is why is the ratio squared? If p0 is the reference pressure level, and p1 is the measured pressure level, why isn't SPL just the log of that ratio, similar to the way sound power level is the log of power level ratio? The primary reason is simply that anything involving decibels is by definition a ratio of powers, and acoustic power is related to the square of the pressure level. -- % Randy Yates % "My Shangri-la has gone away, fading like %% Fuquay-Varina, NC % the Beatles on 'Hey Jude'" %%% 919-577-9882 % %%%% % 'Shangri-La', *A New World Record*, ELO http://www.digitalsignallabs.com Thanks, Randy, and everyone else who answered. I didn't know this one of "those" questions that stirs up an old debate. It helps me to know that a decibel or bel is defined as the log of a ratio of power levels. Gives me something to remember then, that if it's acoustic pressure, or voltage, or anything where its square is related to power, that it's going to be 20x rather than 10x (for decibel). And from there I can remember figure whether it's 3dB or 6 dB that represents (roughly) a doubling of the ratio. Exactly. I'm very glad to see you "got it," Keith. Glad I could help. -- % Randy Yates % "Rollin' and riding and slippin' and %% Fuquay-Varina, NC % sliding, it's magic." %%% 919-577-9882 % %%%% % 'Living' Thing', *A New World Record*, ELO http://www.digitalsignallabs.com |
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