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John Smith
 
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Default Converting 4-wire Speaker/Mic pair into 3-wire Speaker/Mic/Ground

I have a headset that comes with 3 conductors (speaker, mic and ground).
I want to use it to connect to a PC that has separate speaker and mic
jacks (both mono). Should I connect the headset ground to the PC's:

1. Speaker ground; or
2. Mic ground; or
3. Both speaker and mic ground?
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Rob Beech
 
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"John Smith" wrote in message
om...
I have a headset that comes with 3 conductors (speaker, mic and ground).
I want to use it to connect to a PC that has separate speaker and mic
jacks (both mono). Should I connect the headset ground to the PC's:

1. Speaker ground; or
2. Mic ground; or
3. Both speaker and mic ground?


Its not uncommon to have the same ground for a speaker and a mic in a
headset. But they both do need it. (it effectivly completes the circuit)
they both need the ground. So you would need to alter your plugs around
accordingly.

If you look at a stereo jack on a normal pair of headphones. you have 3
connectors. one for left one for right and a ground. Its the same principle.


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normanstrong
 
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"Rob Beech" wrote in message
...

"John Smith" wrote in message
om...
I have a headset that comes with 3 conductors (speaker, mic and

ground).
I want to use it to connect to a PC that has separate speaker and

mic
jacks (both mono). Should I connect the headset ground to the

PC's:

1. Speaker ground; or
2. Mic ground; or
3. Both speaker and mic ground?


Its not uncommon to have the same ground for a speaker and a mic in

a
headset. But they both do need it. (it effectivly completes the

circuit)
they both need the ground. So you would need to alter your plugs

around
accordingly.

If you look at a stereo jack on a normal pair of headphones. you

have 3
connectors. one for left one for right and a ground. Its the same

principle.

I would think that would be a very tricky business. The high current
of the speaker signal would appear on the same ground line as the low
voltage mike signal. The resistance of the ground line would cause a
significant voltage drop that would add (or subtract) from the mike
signal.

I don't know anything about the subject, but that's the first thing
that would occur to me.

Norm Strong


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