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#1
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A little help with a "tank" circuit?
I have forgotten what the governing equation is (more specifically if
the equation involves just "f" or is it "2pi*f"). If I have this 10 mH inductor lying around, what capacitor should I combine it with to create a 200 Hz notch circuit? This is for a full-range coax speaker in a car. I have calculated a value of 63-ish uF for the cap. Am I on track? |
#2
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"dangling entity" wrote in message ps.com... I have forgotten what the governing equation is (more specifically if the equation involves just "f" or is it "2pi*f"). If I have this 10 mH inductor lying around, what capacitor should I combine it with to create a 200 Hz notch circuit? This is for a full-range coax speaker in a car. I have calculated a value of 63-ish uF for the cap. Am I on track? Yes you are right, at resonance: F=1/(2*pi*Square root(L*C) Sorry couldn't find the correct mathamatical symbols. Works out at 200.5 Hz Pete |
#3
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Thanks for postin' in! Time to solder-up...
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#4
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The filter will also have -3dB points of 120 and 360 Hz -- and because of
the complex load there will be a secondary notch of about -2dB around 50 Hz. "dangling entity" wrote in message oups.com... Thanks for postin' in! Time to solder-up... |
#5
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Interesting point about the secondary notch. I've never been exposed
to this side of the design. I guess it is good I would be applying this filter to the upper range speaker rather than the sub. I take it the primary notch specs you have cited are for a "no resistor" filter scenario? If I add in a parallel resistor to tweak the final output, will the -3 dB points change, or does it just affect the depth of the notch frequency mostly? |
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