Home |
Search |
Today's Posts |
#1
Posted to rec.audio.tech
|
|||
|
|||
Port size on new speaker cabinets
Hope this is the right group to ask such a question.
I am trying to build my own speakers from a design I found here... http://www.fane-acoustics.com/public...closure_12.pdf Looking at the size of the vents in this design I am unable to reproduce the way they established the length of the vent ports. Can anyone shed some light on this? According to my own calculations (using a formula I found on internet and in some books) I calculate a length of the vent ports approximately double that of what the speaker manufacturer puts in his design. |
#2
Posted to rec.audio.tech
|
|||
|
|||
Port size on new speaker cabinets
jansb000 wrote: Looking at the size of the vents in this design I am unable to reproduce the way they established the length of the vent ports. Can anyone shed some light on this? According to my own calculations (using a formula I found on internet and in some books) I calculate a length of the vent ports approximately double that of what the speaker manufacturer puts in his design. The port length required depends upon a just a few parameters, * the frequency to which the enclosure is tuned, * the internal volume of the enclosure * the diameter of the port So those are the three parameters you must know in order to determine the length of the port. If any of them are missing, you can't calculate the length. The tuning frequency is constrained by how the overall system is "aligned," and that's determined by the driver and the desired system response function (these two, however, could very well be mutally exclusive). Since in a helmholtz resonator (which is what a ported system is), the resonant frequency is: Fb = 2 pi sqrt( 1/(Cab*Map) ) where Fb is the resonant frequency of the enclosure, Cab is the acoustic compliance of the box, and Map is the acoustic inertance of the port, a little algebra will show you that: Map = 4 pi^2 / (Cab Fb^2) Now you have the acoustic inertance required to achieve that frequency with that enclosure volume. The port supplies the acoustic inertance, and is determined as follows: Map = pl' / S^2 where p is the density of air, l' is the end corrected length of the port, and S is the cross-sectional area of the port, which is, of course, determined by: S = pi d where d is the diameter of the port. Combining these last two: Map = pl' / (pi^2 d^2) (note, all measurements in the mks syste, e.g., meters, kilograms, seconds, etc.). Again, a little algebra tells us that l' = pi^2 d^2 Map / p And finally, l' is the 'end corrected' length: the port is, in effect, slightly longer than the physical length, in a way that's dependent on the diameter. Assume that one end of the port terminates flush with the cabinet wall, and the other is free (even if inside the cabinet), that end correction is: l' ~= l + 0.73d where l is the physical length. One more slight of algebraic hands then gives us: l ~= l' - 0.73d So that's how we get there. Now, to repeat, you HAVE to know the intended enclosure resonant frequency, the volume of the box and the diameter of the port. Without those, you can't determine the length. And, without many more details on your particular case, there is no way to evaluate if the numbers you are getting are right or wrong. |
#3
Posted to rec.audio.tech
|
|||
|
|||
Port size on new speaker cabinets
Could be that since there are two ports in this design, each one would be
half as long as if there was only one. James. ) wrote in message ups.com... According to my own calculations (using a formula I found on internet and in some books) I calculate a length of the vent ports approximately double that of what the speaker manufacturer puts in his design. |
#4
Posted to rec.audio.tech
|
|||
|
|||
Port size on new speaker cabinets
James Lehman wrote: Could be that since there are two ports in this design, each one would be half as long as if there was only one. James. ) Actually, doubling the number of ports would require doubling the length of each to achieve the same effective acoustic inertance, in much the same way that putting two inductors in parallel would require each inductor to be twice that of the desired total inductance. Another way to look at it is that two ports whose diameter is d have a toal corss sectional area twice that of a single port, and wince the length . Since the inertance goes as the length and as the reciprocal of the area, then to achieve the same inertance with twice the area requires twice the length. |
#5
Posted to rec.audio.tech
|
|||
|
|||
Port size on new speaker cabinets
"jansb000" wrote in message
ups.com... Hope this is the right group to ask such a question. I am trying to build my own speakers from a design I found here... http://www.fane-acoustics.com/public...closure_12.pdf Looking at the size of the vents in this design I am unable to reproduce the way they established the length of the vent ports. Can anyone shed some light on this? According to my own calculations (using a formula I found on internet and in some books) I calculate a length of the vent ports approximately double that of what the speaker manufacturer puts in his design. I have a function generater connected to the amp that is connected to the speaker getting tuned.. I connected a digital VOM to speaker and measured the ouput at various frequencies. Since the room acustics and recording speaker's response vary at different frequencies, the test is only good for comparing different port lengths at a given frequency. From that, I was able to tune the ports to a smoother roll-off. Too short gave a boomy response around 50Hz, too long and 40-60 Hz is weakened and too much response down in the nearly unused 30Hz area. The result is smooth efficient bass with usable output down to 30Hz. The 4" ports I used were not very expensive, so I bout an extra to cut it down for the test. John |
#6
Posted to rec.audio.tech
|
|||
|
|||
Port size on new speaker cabinets
Can this process be reversed: Knowing the dimensions of the port, the
cabinet and the thiele-small parameters of the driver and from there calculate the resonant frequency? It strikes me that the cabinet design can be used for two drivers from FANE, namely the Colossus 12MB and the Cresendo 12MB. These drivers have different thiele-small parameters and therefore would result in different tuning of the driver/cabinet combination. |
#7
Posted to rec.audio.tech
|
|||
|
|||
Port size on new speaker cabinets
Can this process be reversed: Knowing the dimensions of the port, the
cabinet and the thiele-small parameters of the driver and from there calculate the resonant frequency? It strikes me that the cabinet design can be used for two drivers from FANE, namely the Colossus 12MB and the Cresendo 12MB. These drivers have different thiele-small parameters and therefore would result in different tuning of the driver/cabinet combination. |
#8
Posted to rec.audio.tech
|
|||
|
|||
Port size on new speaker cabinets
jansb000 wrote: Can this process be reversed: Knowing the dimensions of the port, the cabinet and the thiele-small parameters of the driver and from there calculate the resonant frequency? The enclosure resonant frequency is a function of the port dimensions and the cabinet volume. That's it. So if you have a cabinet of such-and- such dimensions and it has port(s) of so-and-so size, that's all you need to determine what the enclosure resonant frequency is. However, whether that cabinet is at all suitable for any given driver you pick is another issue altogether. If you have a driver in hand, the parameters of the driver and a knowledge of what the desired system response function is supposed to be then determines what cabinet volume is suitable and what the enclosure resonant frequency should be. Thus, it's altogether possible to have a driver and a cabinet and a set of ports that have no business being put together. It strikes me that the cabinet design can be used for two drivers from FANE, namely the Colossus 12MB and the Cresendo 12MB. These drivers have different thiele-small parameters and therefore would result in different tuning of the driver/cabinet combination. Yes, and the fact that they have different Thiele/SMall parameters could very well mean that they need a different cabinet volume than what you have. Selecting the proper cabinet volume is as important a part of the system design function as selecting the cabinet resonant frequency. You can't just stick the driver an any cabinet and try to tune your way to an optimum system response. |
Reply |
Thread Tools | |
Display Modes | |
|
|
Similar Threads | ||||
Thread | Forum | |||
Just for Ludovic | Audio Opinions | |||
Bose 901 Review | General | |||
here is how firewire ports fail | Pro Audio | |||
FS. Tannoy, Altec, Bozak, EV Speaker Cainets | Vacuum Tubes | |||
Enclosure Size & Speaker Placement of Mid Range | Car Audio |