Home |
Search |
Today's Posts |
#11
|
|||
|
|||
On Wed, 01 Sep 2004 16:40:43 -0700, Bob Cain
wrote: Isn't this (and the case of coupled infinitely extended planes) just a special case with no relative motion? Relative motion as we usually think of it is just the DC component of the soundfield created by the Tx. But for our purposes wouldn't it be a better model to think of the relative motion as a separate thing, and outside of the Tx and Rx soundfields? Within those soundfields, especially if they're rigidly coupled, nothing interesting happens. That it is fully coupled in the tube (or infinite plane) means it is received as is by the Rx without giving rise to any Doppler effect. Art's step function derivation shows that. That it is not coupled at all to an Rx in the far, free field is what allows simplification to the standard Doppler equation (which is only valid for a constant v and a single frequency in the Tx spectrum.) Yeah, this is the part that Scott calls reciprocity failure. It's a photographer's pun, but it works. Chris Hornbeck |
Thread Tools | |
Display Modes | |
|
|
Similar Threads | ||||
Thread | Forum | |||
Stereophile Tries To Come Clean About The DiAural Fiasco | Audio Opinions | |||
Experimental Evidence for Dynamic Doppler Shift | Tech | |||
Bob Cain Is In Convulsions: A Doppler Piston Just Got Shoved Up His Tube | Tech | |||
Doppler Distoriton? | Tech | |||
Doppler Distortion - Fact or Fiction | Pro Audio |