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Kevin McMurtrie
 
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Default "Fixed" 8 volt output o-loads eq

200K is way too high. The impedance will be too high to overcome cable
capacitance and electric noise. 1K would be more like it.



In article ,
"MZ" wrote:

PS-

If you use a potentiometer (say, 200k ohms or more range), you can dial in
the ideal value of resistance, then use a resistor of that value as the
permanent solution.

--
Mark
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"MZ" wrote in message
...
The spec in the manual says 55 ohm output impedance. (not 55k)

So does that mean if I build an interconnect with a 55 ohm resistor in
the tip, the signal will be reduced 3 db??

No, that's the output impedance of the head unit. What you need is the
input impedance of the amplifier. Oh yeah, and you may want to reduce

by
more than 3dB.


Oh yeah, the other way to do it is to use 2 resistors and create a voltage
divider.

Really, you don't need to know the input impedance. All it does for you

is
give you a good starting point. If you can't find it out, just assume 20k
ohms.