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Don Pearce wrote:
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Nothing to do with the frequency of the wave or its harmonics. Each
ringing event is separate and is triggered by the broadband energy of
the rising or falling edge.

** Gobbledegook.

Don't be so hasty. I know this is not instantly intuitive, but it is
exactly what happens.

** No it ain't.

The frequency of the ring is determined by
the LC circuit that is being struck by that edge.

** So a linear circuit with a resonance creates a new frequency ?

No.

** You are here claiming it does.

If you do an FFT on an edge,

** Not the situation.

The *square wave* can be band limited to just a few times the ringing frequency.
Only needs ONE harmonic close enough to that frequency to get a damped sine result.

Does not do so with a sine sweep.

If you do a sine sweep you will find the resonant frequency of the ring.

** But not *create* it - the maximum is at the exact same frequency as the input sine.

That is the frequency you will see when you strike it with a
fast rising edge.

** Not the case with a normal, square wave test.



...... Phil