"Kevin McMurtrie" wrote ...
"Richard Crowley" wrote:
"EADGBE" wrote ...
The anode of the diode is attached directly to three of the resistors
as shown.
I have tried to re-create the circuit board traces on the other side.
The cathode connects to what N_Cook has described as an inductor.
Take a look at this photo:
http://i240.photobucket.com/albums/f...e123/DIODE.jpg
Thanks to everyone for your help so far.
Any chance of finding a replacement for this diode?
Depending on what the actual diagram looks like,
it is quite possibly a simple, generic silicon diode
like a 1N4001 (power rectifier) or maybe even a
popular signal diode like a 1N4148, etc. These
are both very common parts that likely cost only
a few cents in production quantities.
I believe it takes at least two transistors. It's a positive feedback
system to compensate for losses in the motor, creating a virtual perfect
motor that doesn't change speeds under load. And that brings about the
second problem...
It *has* likely several transistiors inside the TO-92
plastic package that burned up. Refer to the diagram
for the cited integrated circuit.
The circuit has only one pot so it's not going to work on a worn motor.
The loss compensation is a fixed resistor so it's only good for a motor
in perfect condition.
It doesn't need more than one pot. The regulator
compensates for the variations in the motor. Refer
to the diagram for the cited integrated circuit.
Google is a pro-spamming service.
Agreed.
I will not see your reply if you use Google.
Since the OP is posting from Google, you will have a hard time
following this discussion.