[Mariachi]

At any rate, you'd have to know the length of the wire--there's
nothing magical about the gauge of the wire, it's all a matter of the
total resistance that wire has. So, would be fine with 1" of 18 AWG on
a 750 Watt amplifier, but you'd be in really bad shape if you had to
go 15 feet with the same wire on that same amp. :-)

yes I agree...

Resistance of the wire = Resistivity * Length / Area
R(wire) = p * (L/A)

If you lower the wire by 3 gauges then you have a cross sectional area
increase by a factor of 2.
Therefore, the total resistance decreases by a factor of 2 given that
the resistivity and length are still the same.

So if you want to make a power wire twice as long, you need to
increase A by 2 times also. Therefore it would be the same ratio and
therefore it would be the same total resistance.

So if I have positive power wire with a length 2 meters with a 16
guage cross sectional area...
Resistivity of copper = 1.7 microohm/cm = 1.7 microohm/cm * (1 *
10^(-6) ohms / 1 microohm) * (1 m / 100 cm) = 0.000000017 ohm/m
L = 2 meters
A (16 gauge)= 0.8107 m^2

R(16 GWG wire) = (1.7e-8)*(2/.8107) ohms = 4.194e-8 ohms
R(14 GWG wire) = (1.7e-8)*(2/1.291) ohms = 2.634e-8 ohms

4.194 / 2.634 = 1.59

Resistance decreased by 1.59 times

R(16 GWG) / R(13 GWG) = 2
R(16 GWG) / R(14 GWG) = 1.6