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Antispammer
 
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yupz, a trapeziod. To be exact, it's actually a trapezoid on top of a
rectangle.
Due the 45-75 degree slope, I guess the subs can only be mounted by
increasing the height. They will be firing at the rear at such an angle so
that the sound will be reflex to the front of the vehicle.
It's a Dual 15" box with slot port that I wanted. I have no restrictions on
the box size.
any suggestions?

subs specs
Fs = 28 Hz
Qms = 4.68
Vas = 123.3 liters
Xmax = 32 mm
Xmax (parallel) = 32 mm
Xmax (series) = 32 mm
Sd = 125.6 sq.in
Qes = 1.1
Qes (parallel) = 0.55
Qes (series) = 0.55
Re = 1.9 ohms
Re (parallel) = 0.95 ohm
Re (series) = 3.8 ohms
Z = 2 ohms
Z (parallel) = 1 ohm
Z (series) = 4 ohms
BL = 1.922 lb/A
BL (parallel) = 1.922 lb/A
BL (series) = 3.844 lb/A
Pe = 800 watts
Pe (parallel) = 1600 watts
Pe (series) = 1600 watts
Qts = 0.89
Qts (parallel) = 0.49
Qts (series) = 0.49
1-W SPL = 85.8 dB
1-W SPL (parallel) = 88.7
1-W SPL (series) = 88.7




"Scott Gardner" wrote in message
news
On Wed, 30 Mar 2005 22:28:07 +0800, "AntiSpammer"
wrote:

anyone knows if there is a good tutorial + software calculator on

designing
a trapezium box?
math is killing me...
I have tried searching everywhere.....

What exactly do you mean by "trapezium"? Americans usually use this
to describe a four-sided figure with no parallel sides. To the
British, it's a four-sided figure with two parallel sides (what we in
America usually call a "trapezoid".

If you have two parallel sides, the area is 0.5 X (a+b) X h, where a
and b are the lengths of the two parallel sides, and h is the height.
After you find that, multiply by the depth of the box to get the
volume.

If you have no parallel sides at all, the math gets trickier.
Describe exactly how your enclosure is shaped, and I can probably work
out a formula for the volume.


--
Scott Gardner

"You don't need to fire the rig foreman that just blew the top off the

wellhead, cause you know for damned sure he'll never do it again." (Ron
Gardner)