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Mike Rivers
 
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In article writes:

I found
an old cable in the bottom of a drawer that has the above-mentioned amphenol
on on end and a 1/4 phone jacl on the other. So, I cut off the 1/4 jack and
was going to put on a modern XLR. After I cut the cable, I noticed that
this cable only contains one inner wire and the "shield". In other words,
we have only two conductors here to connect to the modern XLR. Now, perhaps
the shield goes to pin 1 of the xlr, but then we have only one conductor
left over.


That's a cable that's designed to be plugged into a "high impedance"
input, with the switch on the microphone set to the high impedance
position.

By the way, I checked the Shure web site and found the document you were
referring to, thank you. But with my extremely limited electronics
knowledge, it really makes no sense to me.


In that case, you probably wouldn't understand the explanation, but
if you disassemble the connector on the microphone end of the cable,
you'll see how it's wired.

You really shouldn't use that cable with an XLR connector, but if you
insist, connect the center conductor to pin 2 and connect the shield
to pins 1 and 3. Be sure to turn the switch on the mic to M or L. Then
plug it in, and when you hear how bad it sounds, you'll have second
thoughts about whether it's worth the time and trouble to make the
proper cable.

Someone gave me two 55s and when I listened to them, I decided that
when I find a nice piece of walnut to mount them on, I'm going to turn
them into a hat rack. I could probably make a killing selling them on
eBay but I want to spare someone else the agony.




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