The Ghost wrote:
What do you mean by "flow velocity?" It's not discussed or defined in any
of my reference books on acoustics, and I have most if not all of them.
Define your terms........Sp'(t), Ra, Vd, etc. If you have a closed form
solution, present it.
I'm not an acoustics specialist, as is obvious, and am not
terribly concerned about satisfying them with terms. What I
mean is the velocity of the acoustic air flow passing a plane
in units of distance/time. If there is a more correct term
I'd be happy to know it.
Definition of terms:
Vp(t) is the velocity of a particle normally at rest at the
origin as an acoustic wave goes through it in MKS units of
meter/second.
Sp(t) is the position of that particle in meters.
Vf(t) = Vp(t+Sp(t)/c) is the flow velocity at the origin
as a function of the particle velocity Vp(t) and position
Sp(t) defined above. This relationship holds everywhere,
not just near a driver.
Vd(t) is the velocity of a driver face at rest at the origin.
Sd(t) is it the position of the driver face.
Vp(d,t) = Vd(t-d/c) is the velocity of a particle normally
at rest at the position d as an acoustic wave created by a
driver at the origin goes past it. It is also in MKS units
of meter/second.
Sp(d,t) = Sd(t-d/c) is the positon of that same particle
about position d in units of the meter.
Ra is the acoustic impedence of air in Pascal*sec/meter. In
a tube it is homogenious and isoptropic with an approximate
value of 300 Pascal*sec/meter.
Vf(d,t) = Vd(t-(d-Sp(d,t))/c) is the velocity of particles
passing a plane at d in meter/sec.
P(d,t) = Ra*Vf(d,t) is the pressure at that plane.
On closed forms:
If the driver velocity function of time has a closed form
indefinite integral, the application of my expression for
Vf(d,t) to obtain a closed form for the flow velocity and
pressure should be obvious.
For example if the velocity function of the driver is
Vd(t) = Al*sin(Wl*t) + Ah*sin(Wh*t)
then
Sd(t) = -((Al/Wl)cos(Wl*t) + (Ah/Wh)cos(Wh*t))
and
Sp(d,t) = -((Al/Wl)cos(Wl*(t-d/c)) + (Ah/Wh)cos(Wh*(t-d/c))
Vp(d,t) = Al*sin(Wl*(t-(d-Sp(d,t))/c)) + Ah*sin(Wh*(t-(d-Sp(d,t))/c))
I haven't bothered to do the algebraic substitution of the
penultimate equation into the final one. With that, it is an
exact closed form solution for two sinusoids.
Bob
--
"Things should be described as simply as possible, but no
simpler."
A. Einstein
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