Randy Ott
August 6th 03, 09:38 PM
Dear what-ever-your-name-is,
Using four 0.8 Ohm secondaries, you can acheive the following:
All 4 in parallel = 0.8 Ohms
2 in series paralled with two more in series = 3.2 Ohms
3 in series = 7.2 Ohms.
All four in series = 12.8 Ohms.
Good luck,
Randy Ott
"·à¤l¤f" > wrote in message
...
> How to get 0.8 Ohm 3.2 Ohm 7.4 Ohm and 12.5 Ohm using four 0.8 Ohm
> secondaries in:
> http://stiftsbogtrykkeriet.dk/~mcs/Transformer.html
>
>
>
>
---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
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Using four 0.8 Ohm secondaries, you can acheive the following:
All 4 in parallel = 0.8 Ohms
2 in series paralled with two more in series = 3.2 Ohms
3 in series = 7.2 Ohms.
All four in series = 12.8 Ohms.
Good luck,
Randy Ott
"·à¤l¤f" > wrote in message
...
> How to get 0.8 Ohm 3.2 Ohm 7.4 Ohm and 12.5 Ohm using four 0.8 Ohm
> secondaries in:
> http://stiftsbogtrykkeriet.dk/~mcs/Transformer.html
>
>
>
>
---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.504 / Virus Database: 302 - Release Date: 7/24/2003